Skip to main content
Ch.20 - Nuclear Chemistry
Chapter 20, Problem 60

Radioactive decay exhibits a first-order rate law, rate = -∆N/∆t = kN, where N denotes the number of radio-active nuclei present at time t. The half-life of strontium-90, a dangerous nuclear fission product, is 29 years. (a) What fraction of the strontium-90 remains after three half-lives?

Verified step by step guidance
1
Understand the concept of half-life: The half-life of a radioactive substance is the time it takes for half of the radioactive nuclei to decay.
Identify the number of half-lives passed: In this problem, three half-lives have passed for strontium-90.
Calculate the fraction remaining after each half-life: After one half-life, half of the original amount remains, which is \(\frac{1}{2}\) of the original amount.
Apply the half-life decay successively for each half-life: After the second half-life, half of the remaining amount from the first half-life will decay, leaving \(\frac{1}{2} \times \frac{1}{2} = \frac{1}{4}\) of the original amount.
Calculate the fraction remaining after the third half-life: Similarly, after the third half-life, half of the remaining amount from the second half-life will decay, leaving \(\frac{1}{4} \times \frac{1}{2} = \frac{1}{8}\) of the original amount.

Verified Solution

Video duration:
1m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

First-Order Kinetics

First-order kinetics refers to a reaction rate that is directly proportional to the concentration of one reactant. In the context of radioactive decay, this means that the rate at which a radioactive substance decays is dependent on the number of undecayed nuclei present. The mathematical representation, rate = -∆N/∆t = kN, indicates that as the number of nuclei decreases, the rate of decay also decreases.
Recommended video:
Guided course
02:29
First-Order Reactions

Half-Life

The half-life of a radioactive substance is the time required for half of the radioactive nuclei in a sample to decay. This concept is crucial for understanding the decay process, as it provides a consistent measure of how quickly a substance will lose its radioactivity. For strontium-90, with a half-life of 29 years, after each half-life, the remaining quantity of the substance is halved.
Recommended video:
Guided course
02:17
Zero-Order Half-life

Exponential Decay

Exponential decay describes the process by which a quantity decreases at a rate proportional to its current value. In radioactive decay, this means that after each half-life, the amount of the substance remaining can be calculated using the formula N(t) = N0 * (1/2)^(t/T), where N0 is the initial quantity, t is the elapsed time, and T is the half-life. This concept helps in determining the fraction of strontium-90 remaining after multiple half-lives.
Recommended video:
Related Practice
Textbook Question
The decay constant of plutonium-239, a waste product from nuclear reactors, is 2.88 * 10-5 year - 1. What is the half-life of 239Pu?
1137
views
Textbook Question
Polonium-209, an a emitter, has a half-life of 102 years. How many alpha particles are emitted in 1.0 s from a 1.0 ng sample of 209Po?
945
views
Textbook Question
A sample of 37Ar undergoes 8540 disintegrations/min initially but undergoes 6990 disintegrations/min after 10.0 days. What is the half-life of 37Ar in days?
320
views
Textbook Question
Potassium ion, K+, is present in most foods and is an essen-tial nutrient in the human body. Potassium-40, however, which has a natural abundance of 0.0117%, is radioactive with t1/2 = 1.25 x 10^9 years. What is the decay constant of 40K? How many 40K+ ions are present in 1.00 g of KCl? How many disintegration/s does 1.00 g of KCl undergo?
682
views
Textbook Question
The electronic systems on the New Horizons spacecraft, which launched on January 19, 2006, and reached its closest approach to Pluto on July 14, 2015, were powered by elec-tricity generated by heat. The heat came from the radioac-tive decay of 238Pu in the 11 kg of 238PuO2 fuel onboard. The generator provided 240 W when the spacecraft was launched. If the power output is directly proportional to the amount of 238Pu in the generator, what was the power output when the spacecraft reached Pluto? The half-life of 238Pu is 87.7 y.
303
views
Open Question
The radioisotope 226Ac can decay by any of three different nuclear processes: alpha emission, beta emission, or electron capture. (a) Write a balanced nuclear equation for the decay of 226Ac by each decay mode.