Skip to main content
Ch.17 - Applications of Aqueous Equilibria
Chapter 17, Problem 2

What is the percent dissociation in a solution that is 0.50 M in acetic acid (CH3CO2H) and 0.10 M in sodium acetate (NaCH3CO2)? (Ka = 1.8 x 10^-5) (a) 0.018% (b) 0.090% (c) 7.2 x 10^-3% (d) 2.3%

Verified step by step guidance
1
Identify the components of the solution: acetic acid (CH3CO2H) is a weak acid, and sodium acetate (NaCH3CO2) is its conjugate base. This is a buffer solution.
Use the Henderson-Hasselbalch equation to find the pH of the buffer solution: \( \text{pH} = \text{pKa} + \log \left( \frac{[\text{A}^-]}{[\text{HA}]} \right) \), where \([\text{A}^-]\) is the concentration of the acetate ion and \([\text{HA}]\) is the concentration of acetic acid.
Calculate the pKa from the given Ka: \( \text{pKa} = -\log(1.8 \times 10^{-5}) \).
Substitute the concentrations of acetic acid and acetate ion into the Henderson-Hasselbalch equation to find the pH.
Use the pH to determine the percent dissociation of acetic acid: \( \% \text{dissociation} = \left( \frac{[\text{H}^+]}{[\text{HA}]} \right) \times 100 \), where \([\text{H}^+]\) is the concentration of hydrogen ions calculated from the pH.