What is the molar solubility of Ag2SO3 in water? The solubility-product constant for silver sulfite is 1.5 x 10^-14 at 25 °C. (a) 1.2 x 10^-7 M (b) 2.0 x 10^-5 M (c) 8.7 x 10^-8 M (d) 1.6 x 10^-5 M
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1
Write the balanced dissolution equation for Ag2SO3: Ag2SO3(s) \rightleftharpoons 2Ag^+(aq) + SO3^{2-}(aq).
Express the solubility product constant (K_{sp}) in terms of the concentrations of the ions: K_{sp} = [Ag^+]^2[SO3^{2-}].
Let the molar solubility of Ag2SO3 be 's'. Then, [Ag^+] = 2s and [SO3^{2-}] = s.
Substitute the expressions for the ion concentrations into the K_{sp} expression: K_{sp} = (2s)^2(s) = 4s^3.
Set the K_{sp} expression equal to the given solubility-product constant and solve for 's': 4s^3 = 1.5 \times 10^{-14}.