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Ch.15 - Chemical Equilibrium
Chapter 15, Problem 52

Identify the true statement about the rate of the forward and reverse reaction once a reaction has reached equilibrium. (a) The rate of the forward reaction and the reverse reaction is zero. (b) The rate of the forward reaction is greater than the rate of the reverse reaction. (c) The rate of the reverse reaction is greater than the rate of the forward reaction. (d) The rate of the forward reaction is equal to the rate of the reverse reaction.

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Understand the concept of chemical equilibrium, which occurs when the rate of the forward reaction equals the rate of the reverse reaction, and the concentrations of reactants and products remain constant over time.
Analyze option (a): If both the forward and reverse reactions had a rate of zero at equilibrium, no reactions would be occurring, which contradicts the dynamic nature of equilibrium where reactions continue to occur.
Evaluate option (b) and (c): If the rate of the forward reaction was greater than the reverse, or vice versa, the concentrations of reactants and products would continue to change, indicating that the system has not yet reached equilibrium.
Consider option (d): At equilibrium, the ongoing forward and reverse reactions occur at the same rate, which keeps the overall concentrations of reactants and products constant.
Conclude that the correct statement about the rates of the forward and reverse reactions at equilibrium is that they are equal, supporting option (d).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Chemical Equilibrium

Chemical equilibrium occurs in a reversible reaction when the rates of the forward and reverse reactions become equal, resulting in no net change in the concentrations of reactants and products. At this point, the system is in a state of balance, and the concentrations remain constant over time.
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Reaction Rates

The rate of a reaction refers to the speed at which reactants are converted into products. In a reversible reaction, the forward rate is the speed of the reaction forming products, while the reverse rate is the speed of the reaction forming reactants. Understanding these rates is crucial for analyzing the behavior of a system at equilibrium.
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Dynamic Nature of Equilibrium

Equilibrium is dynamic, meaning that even though the concentrations of reactants and products remain constant, both the forward and reverse reactions continue to occur at equal rates. This dynamic balance is essential for understanding how systems respond to changes in conditions, such as concentration, temperature, or pressure.
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Related Practice
Textbook Question
The following pictures represent the initial and equilibrium states for the exothermic decomposition of gaseous A mol- ecules (red) to give gaseous B molecules (blue). (b) Will the number of A molecules in the equilibrium mix- ture increase, decrease, or remain the same after each of the following changes? Explain. (3) Increasing the pressure by adding an inert gas
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Textbook Question

The following pictures represent the initial and equilibrium states for the exothermic decomposition of gaseous A mol- ecules (red) to give gaseous B molecules (blue). (a) Write a balanced chemical equation for the reaction.

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Textbook Question

The following pictures represent the initial and equilibrium states for the exothermic reaction of solid A (red) with gas- eous B2 (blue) to give gaseous AB. (a) Write a balanced chemical equation for the reaction.

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Open Question
Identify the true statement about the concentrations of A and B once the reaction A ⇌ B has reached equilibrium. (a) The concentration of A equals the concentration of B. (b) The concentrations of A and B are constant. (c) The concentration of A decreases and the concentration of B increases. (d) The concentration of B decreases and the concentration of A increases.
Open Question
For each of the following equilibria, write the equilibrium constant expression for Kc. (a) CH4(g) + H2O(g) ⇌ CO(g) + 3 H2(g) (b) 3 F2(g) + Cl2(g) ⇌ 2 ClF3(g) (c) H2(g) + F2(g) ⇌ 2 HF(g)
Open Question
For each of the following equilibria, write the equilibrium constant expression for Kc. (a) 2 C2H4(g) + O2(g) ⇌ 2 CH3CHO(g) (b) CO(g) + H2O(g) ⇌ CO2(g) + H2(g) (c) 4 NH3(g) + 5 O2(g) ⇌ 4 NO(g) + 6 H2O(g)