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Ch.15 - Chemical Equilibrium
Chapter 15, Problem 89

Gaseous indium dihydride is formed from the elements at elevated temperature: ln(g) + H2(g) ightarrow lnH2(g), Kp = 1.48 at 973 K. Partial pressures measured in a reaction vessel are: P_in = 0.0600 atm, P_H2 = 0.0350 atm, P_lnH2 = 0.0760 atm. (b) Determine the equilibrium partial pressures of all the gases.

Verified step by step guidance
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Step 1: Write the expression for the equilibrium constant Kp for the reaction: \( \text{In}(g) + \text{H}_2(g) \rightleftharpoons \text{InH}_2(g) \). The expression is given by \( K_p = \frac{P_{\text{InH}_2}}{P_{\text{In}} \times P_{\text{H}_2}} \).
Step 2: Substitute the given partial pressures into the Kp expression: \( K_p = \frac{0.0760}{0.0600 \times 0.0350} \). Calculate this value to check if the system is at equilibrium.
Step 3: Compare the calculated Kp value with the given Kp (1.48). If they are equal, the system is at equilibrium. If not, determine the direction in which the reaction will shift to reach equilibrium.
Step 4: If the reaction is not at equilibrium, use an ICE (Initial, Change, Equilibrium) table to determine the changes in partial pressures needed to reach equilibrium. Define the change in pressure as \( x \) and adjust the initial pressures accordingly.
Step 5: Substitute the equilibrium expressions from the ICE table back into the Kp expression and solve for \( x \). Use this value to find the equilibrium partial pressures of all gases.
Related Practice
Open Question
A sample of HI 19.30 * 10^-3 mol^2 was placed in an empty 2.00-L container at 1000 K. After equilibrium was reached, the concentration of I2 was 6.29 * 10^-4 M. Calculate the value of Kc at 1000 K for the reaction H2(g) + I2(g) ⇌ 2 HI(g).
Textbook Question
The industrial solvent ethyl acetate is produced by the reac-tion of acetic acid with ethanol: CH3CO2H1soln2 + CH3CH2OH1soln2 ∆ CH3CO2CH2CH31soln2 + H2O1soln2 Ethyl acetate (b) A solution prepared by mixing 1.00 mol of acetic acid and 1.00 mol of ethanol contains 0.65 mol of ethyl ace- tate at equilibrium. Calculate the value of Kc. Explain why you can calculate K without knowing the volume of the solution.
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Open Question
A characteristic reaction of ethyl acetate is hydrolysis, the reverse of the reaction in Problem 15.87. Write the equilibrium equation for the hydrolysis of ethyl acetate, and use the data in Problem 15.87 to calculate Kc for the hydrolysis reaction.
Textbook Question
The following reaction, which has Kc = 0.145 at 298 K, takes place in carbon tetrachloride solution: 2 BrCl1soln2 ∆ Br21soln2 + Cl21soln2 A measurement of the concentrations shows 3BrCl4 = 0.050 M, 3Br24 = 0.035 M, and 3Cl24 = 0.030 M. (b) Determine the equilibrium concentrations of BrCl, Br1, and Cl2.
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Textbook Question
An equilibrium mixture of N2, H2, and NH3 at 700 K con- tains 0.036 M N2 and 0.15 M H2. At this temperature, Kc for the reaction N21g2 + 3 H21g2 ∆ 2 NH31g2 is 0.29. What is the concentration of NH3?
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Open Question
An equilibrium mixture of O2, SO2, and SO3 contains equal concentrations of SO2 and SO3. Calculate the concentration of O2 if Kc = 2.7 * 10^2 for the reaction 2 SO2(g) + O2(g) ⇌ 2 SO3(g).