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Ch.15 - Chemical Equilibrium
Chapter 15, Problem 104

15.104 Consider the reaction C(s) + CO2(g) ⇌ 2 CO(g). When 1.50 mol of CO2 and an excess of solid carbon are heated in a 20.0-L container at 1100 K, the equilibrium concentration of CO is 7.00 x 10^-2 M. (a) What is the equilibrium concentration of CO2? (b) What is the value of the equilibrium constant Kc at 1100 K?

Verified step by step guidance
1
Step 1: Write the balanced chemical equation for the reaction: C(s) + CO_2(g) ⇌ 2 CO(g).
Step 2: Use the information given to set up an ICE (Initial, Change, Equilibrium) table. Initially, you have 1.50 mol of CO_2 in a 20.0 L container, so the initial concentration of CO_2 is 1.50 mol / 20.0 L. The initial concentration of CO is 0 M.
Step 3: Define the change in concentration for CO_2 and CO. Let x be the change in concentration of CO_2 that reacts. Since the stoichiometry of the reaction shows that 1 mol of CO_2 produces 2 mol of CO, the change in concentration of CO will be 2x.
Step 4: Use the equilibrium concentration of CO, which is given as 7.00 x 10^-2 M, to find x. Since the change in concentration of CO is 2x, set 2x equal to 7.00 x 10^-2 M and solve for x.
Step 5: Calculate the equilibrium concentration of CO_2 using the initial concentration and the change in concentration (x). Then, use the equilibrium concentrations of CO and CO_2 to calculate the equilibrium constant K_c using the expression K_c = [CO]^2 / [CO_2].
Related Practice
Open Question
A 5.00-L reaction vessel is filled with 1.00 mol of H2, 1.00 mol of I2, and 2.50 mol of HI. Calculate the equilibrium concentrations of H2, I2, and HI at 500 K. The equilibrium constant Kc at 500 K for the reaction H2(g) + I2(g) ⇌ 2 HI(g) is 129.
Textbook Question
At 1000 K, the value of Kc for the reaction C1s2 + H2O1g2 ∆ CO1g2 + H21g2 is 3.0 * 10-2. Calculate the equilibrium concentrations of H2O, CO2, and H2 in a reac- tion mixture obtained by heating 6.00 mol of steam and an excess of solid carbon in a 5.00-L container. What is the molar composition of the equilibrium mixture?
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Open Question
When 1.000 mol of PCl5 is introduced into a 5.000-L container at 500 K, 78.50% of the PCl5 dissociates to give an equilibrium mixture of PCl5, PCl3, and Cl2: PCl5(g) ⇌ PCl3(g) + Cl2(g). (a) Calculate the values of Kc and Kp.
Open Question
The equilibrium constant Kp for the gas-phase thermal decomposition of tert-butyl chloride is 3.45 at 500 K: CH3C(CH3)2Cl(g) ↔ CH2=C(CH3)2(g) + HCl(g). (b) Calculate the molar concentrations of reactants and products in an equilibrium mixture obtained by heating 1.00 mol of tert-butyl chloride in a 5.00-L vessel at 500 K. (c) A mixture of isobutylene (0.400 atm partial pressure at 500 K) and HCl (0.600 atm partial pressure at 500 K) is allowed to reach equilibrium at 500 K. What are the equilibrium partial pressures of tert-butyl chloride, isobutylene, and HCl?
Textbook Question
At 100 °C, Kc = 4.72 for the reaction 2 NO21g2 ∆ N2O41g2. An empty 10.0-L flask is filled with 4.60 g of NO2 at 100 °C. What is the total pressure in the flask at equilibrium?
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Open Question
At 25 °C, Kc = 216 for the reaction 2 NO2(g) ⇌ N2O4(g). A 1.00-L flask containing a mixture of NO2 and N2O4 at 25 °C has a total pressure of 1.50 atm. What is the partial pressure of each gas?