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Ch.13 - Solutions & Their Properties
Chapter 13, Problem 149a

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dissolving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (b) What mass of MClx is formed? (a) How many moles of H2 gas are evolved?

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Step 1: Use the ideal gas law to calculate the number of moles of H2 gas evolved. The ideal gas law is given by PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Step 2: Convert the given pressure from mm Hg to atm by using the conversion factor 1 atm = 760 mm Hg. Then, convert the temperature from Celsius to Kelvin by adding 273.15 to the Celsius temperature.
Step 3: Substitute the values of P (in atm), V (in liters), R (0.0821 L·atm/mol·K), and T (in Kelvin) into the ideal gas law equation to solve for n, the number of moles of H2 gas.
Step 4: To find the mass of MClx formed, use the freezing point depression formula: ΔTf = i * Kf * m, where ΔTf is the change in freezing point, i is the van't Hoff factor, Kf is the freezing point depression constant for water (1.86 °C·kg/mol), and m is the molality of the solution.
Step 5: Calculate the molality (m) of the solution using the change in freezing point and the given mass of water. Then, use the molality to find the moles of MClx, and finally, calculate the mass of MClx using its molar mass.

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Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (c) What is the molality of particles (ions) in the solution of MClx?

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Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (e) What are the formula and molecular weight of MClx?

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Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (f) What is the identity of the metal M?

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