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Ch.9 - Molecular Geometry and Bonding Theories

Chapter 9, Problem 33c

Consider the following XF4 ions: PF4-, BrF4-, ClF4+, and AlF4-. (c) Which of the ions will have an octahedral electron-domain geometry?

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Hi everyone here we have a question telling us that iodine tri chloride, tetra chlor. Oh bar you and I, nitrogen chloride and aluminum tetrachloride are X. CL four ions which has Trigano by pyramidal electron domain geometry. So we're going to start off with our iodine track cool ride. It has an iodine with a lone pair surrounded by four corinne and that makes it an A. X. Five molecule which makes it Trigon all by pyramidal. Next we have tetra chloral boring a guide. It has boron in the middle surrounded by four chorines. So it has four groups around it making it a. x. four which is not Trigana by pyramidal. Next we have our nitrogen tetrachloride. It has a nitrogen in the middle surrounded by four chlorine and no long pairs. Making it an a. x. four which is not Trigon will buy pyramidal. And lastly we have aluminum tetrachloride And it has aluminum in the middle surrounded by four chlorine. Making it an X. For which is not Trigon all by pyramidal. So our answer here is iodine tetrachloride. Thank you for watching. Bye.