Skip to main content
Ch.6 - Electronic Structure of Atoms
Chapter 6, Problem 38a

Indicate whether energy is emitted or absorbed when the following electronic transitions occur in hydrogen: a. from n = 3 to n = 6

Verified step by step guidance
1
insert step 1> Determine the initial and final energy levels of the electron in the hydrogen atom. Here, the electron transitions from n = 3 to n = 6.
insert step 2> Recall that energy is absorbed when an electron moves to a higher energy level (higher n value) and emitted when it moves to a lower energy level (lower n value).
insert step 3> Since the electron is moving from n = 3 to n = 6, it is transitioning to a higher energy level.
insert step 4> Conclude that energy is absorbed during this transition because the electron is moving to a higher energy level.
insert step 5> Remember that the energy difference between levels can be calculated using the Rydberg formula if needed, but the key concept here is the direction of the transition.

Verified Solution

Video duration:
2m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Energy Levels in Hydrogen

In hydrogen, electrons occupy discrete energy levels, denoted by quantum numbers (n). The energy associated with each level increases with n, meaning that higher levels (larger n) have more energy. When an electron transitions between these levels, the difference in energy determines whether energy is absorbed or emitted.
Recommended video:
Guided course
01:22
Hydrogenation Reactions

Absorption and Emission of Energy

When an electron moves from a lower energy level to a higher one (e.g., n = 3 to n = 6), it must absorb energy, typically in the form of a photon. Conversely, when an electron falls from a higher energy level to a lower one, energy is emitted. This principle is fundamental in understanding atomic spectra and the behavior of electrons in atoms.
Recommended video:
Guided course
01:51
Emission Spectra

Quantum Mechanics and Photons

Quantum mechanics describes the behavior of particles at atomic and subatomic levels. Photons are the quanta of light and carry energy proportional to their frequency. The energy of a photon can be calculated using the equation E = hf, where h is Planck's constant and f is the frequency. This relationship is crucial for understanding how energy is exchanged during electronic transitions.
Recommended video:
Guided course
01:
Introduction to Quantum Mechanics
Related Practice
Textbook Question

Classify each of the following statements as either true or false: (a) A hydrogen atom in the n = 3 state can emit light at only two specific wavelengths (b) a hydrogen atom in the n = 2 state is at a lower energy than one in the n = 1 state (c) the energy of an emitted photon equals the energy difference of the two states involved in the emission.

661
views
Textbook Question

Is energy emitted or absorbed when the following electronic transitions occur in hydrogen? a. from n = 4 to n = 2

2
views
Textbook Question

Is energy emitted or absorbed when the following electronic transitions occur in hydrogen? b. from an orbit of radius 2.12 Å to one of radius 8.46 Å

2
views
Textbook Question

a. Using Equation 6.5, calculate the energy of an electron in the hydrogen atom when n = 2 and when n = 6. Calculate the wavelength of the radiation released when an electron moves from n = 6 to n = 2.

3
views
Textbook Question

The visible emission lines observed by Balmer all involved nf = 2. (a) Which of the following is the best explanation of why the lines with nf = 3 are not observed in the visible portion of the spectrum: (i) Transitions to nf = 3 are not allowed to happen, (ii) transitions to nf = 3 emit photons in the infrared portion of the spectrum, (iii) transitions to nf = 3 emit photons in the ultraviolet portion of the spectrum, or (iv) transitions to nf = 3 emit photons that are at exactly the same wavelengths as those to nf = 2.

1104
views
Textbook Question

The visible emission lines observed by Balmer all involved nf = 2. (b) Calculate the wavelengths of the first three lines in the Balmer series—those for which ni = 3, 4, and 5—and identify these lines in the emission spectrum shown in Figure 6.11.

1280
views