The Sun supplies about 1.0 kilowatt of energy for each square meter of surface area (1.0 kW/m², where a watt=1 J/s). Plants produce the equivalent of about 0.20 g of sucrose (C12H22O11) per hour per square meter. Assuming that the sucrose is produced as follows, calculate the percentage of sunlight used to produce sucrose. 12 CO2(g) + 11 H2O(l) → C12H22O11 + 12 O2(g) H = 5645 kJ

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Hi everyone for this problem, we're told that .9 kg of carbon dioxide is produced per day per human, assume that all of this carbon dioxide comes from the metabolism of glucose as shown in the following reaction and were also given the change of entropy, About 75% of the energy generated is used for daily basic functions and 25% is used to maintain electric potential and cellular functions. We need to calculate the energy generated for daily basic functions and kilowatts based on the carbon dioxide produced per day. So we know that we have 0.9 kg of carbon dioxide produced per day. So that is where we're going to start here. And we need to go from kg produced per day, two kilowatts. Okay, so let's go ahead and start off with what we know. So we know that we have 0.9 kilograms of carbon dioxide produced per day. Okay, So we need to go from kilograms to grams and we do that using unit conversion. So in one kg of carbon dioxide we have 1000 g of carbon dioxide. And from here we want to go from grams produced Per day, two seconds. Okay, When we go from, so that's our goal here. We want to go from kg produced per day, two g produced per second. And let's go ahead an do that first. So we have in one day, There is 24 hours. Okay, so let's see what cancels so far we have kilograms cancels. We have our day canceled. Okay, remember we want to go from g two g produced per second. Okay, so now we need to go from hours to seconds. Okay, so in one hour We have 60 minutes And in one minute There is 60 seconds. Okay, So this gives us 0. 16 g of carbon dioxide per second. Okay, so now we can well that's going to be our second starting point. So now that we know how much grams of carbon dioxide we produce per second, we can go from grams per second to kilowatts. Okay, We need the molar mass of carbon dioxide here and so and one more of carbon dioxide. We have using the periodic table molar mass of 44. g of carbon dioxide And using the unit conversion, they gave us the following reaction along with its change in entropy. So we're going to use that as a unit conversion. So looking at our equation, we see we have six moles of carbon dioxide. So for every six moles of carbon dioxide we have 2803 Killah Jewels. Okay, so for six moles of carbon dioxide there is 2803 Killah jewels of energy generated. Okay, And and we want this And jewels so we're going to go from Killer Jewels, two jewels. So in one killer jule We have jewels. And so jules per second is what is watts. Okay, so let's see what cancels Here. We have our grams cancel, We have our moles cancel. We have killer jewels, cancel. So jules per second is what we know as watts. Okay, so this answer here is going to be what we get in Watts. So we get 110. jewels per second. And this is the same as Watts. And the question asks us for this in kilowatts. So we need to go from From watts to kW. And so we do that by dividing by 1000. Okay, So when we divide by 1000, we get 0.111 kilowatts. And that is our final answer. This is the energy generated and kilowatts based on carbon dioxide produced per day. That's the end of this problem. I hope this was helpful.

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Key Concepts

Photosynthesis

Energy Conversion Efficiency

Thermochemical Equation