Write a balanced equation for each of the following reactions:

a. Diborane reacts with water to form boric acid and molecular hydrogen.

Video transcript

Welcome back, everyone. Write a balanced chemical equation for the reaction of tetra Bora with water to form boric acid and hydrogen gas. As the problem suggests, our reactants are tetra boring specifically B 4h 10. We are not required to include the states of matter. So we're just writing our second region which is water and we know that water is HTO right? For the product side, we are producing boric acid H three bo three as well as hydrogen gas. And we have to recall that hydrogen gas is diatomic. So we're including two and now we are ready to balance it. First of all, we're going to begin by balancing Boen because Boen is present in only one of our reactants and one of our products. So if we begin with Warren, we first of all have four Boren Adams on the left producing one born atom on the right. So that means we need to multiply one born by four and this is done by adding a coefficient of four, right. So now we have four born atoms on the right four on the left. Now we want to balance hydrogen and oxygen as well. And we are going to choose oxygen due to the same reason oxygen is only present in water and also boric acid while hydrogen is present in multiple species. So if we look at oxygen, we have one oxygen atom on the left. And now we are producing four, multiplied by three that gives us 12 oxygens. So we essentially want to multiply one oxygen by 12 to balance it out. And we are adding a coefficient of 12. And finally, we want to count the number of hydrogens on the left, we have 10 plus 12 multiplied by two, that gives us 24. That's the number of hains on the left. On the right, we have four multiplied by three, which is 12 plus two coming from age two. So if we simplify that we have 34 hydrogens producing 14, now, in order to balance hydrogens, we can simply add a missing coefficient for H two. So we can just say 12 plus two X, right? Why not? Because X will be a multiple of two and that will be our coefficient. So we can say that 34 hydrogens produce 12 hydrogens for boric acid plus two X. And if we solve this equation, we can essentially subtract 12 from both sides to get the value of X. So we can say that 34 equals 12 plus two X and therefore 22 equals to X which gives us the value of X equal to 11 and that will be our coefficient and therefore we have our balanced equation. Let's label it as our final answer. Thank you for watching.