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Ch.21 - Nuclear Chemistry

Chapter 21, Problem 2

Write the balanced nuclear equation for the reaction represented by the diagram shown here. [Section 21.2]

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welcome back everyone. We need to provide the balanced equation for the nuclear reactions shown in the image below. So recognize that on our Y access. We have our number of neutrons for the new Clyde and then we have the number of protons on the X axis for the new Clyde. And so we would also recognize that we have our target or yeah, target new Clyde, which is this first point at the end of our arrow, technically our reactant. And then we have our product new glide at the arrowhead. And so we're going to go ahead and begin by writing out what we know so far. Based on the diagram given. So based on our diagram, we can say that our reactant has 62 neutrons and it has protons. And we see that just by looking at our Y axis 62 neutrons and at our X axis we have 47 protons. So now that we have that cleared away, we can write out a symbol where we see that atomic number 47 on the periodic table corresponds to the atom of silver on our periodic table. A. G. And so to write out our symbol, we so far have a G. And then 47. Because we recall that our number of protons is also equal to our atomic number, which is easy and describes again our number of protons. So we have our atomic number written out so far. Now we're missing our value for a which we recall is atomic mass. And we would recall that our value for a atomic mass Is found by taking the number of protons and adding that to a number of neutrons. So right now we know our number of protons and neutrons. So we would take our 62 Neutrons and add that to our 47 protons. And that's going to give us a mass number of 109. And so we would say that now our symbol is going to be 109 silver as our isotope with the atomic number 47. So this is going to be the first part of our reaction, which is our reactant. So now we have our reactant. We're going to focus on getting now our product or our target or sorry, product, new Clyde. So for our products according to the diagram, we have 61 neutrons and 48 protons. So writing that out 61 neutrons, 48 protons and so on our periodic table. 48 protons or the atomic number 48 corresponds to our atom, which will see as cadmium cd. And so writing out the symbols so far, we would have cadmium with the atomic number 48, which tells us that we have 48 protons as given in the chart or diagram here. And now we need to figure out mass number by taking our 48 protons adding that to our 61 neutrons. That's going to give us a mass number of also 109. And so we would have our isotope 109 cadmium as our product. So now we have at least our product and our reactant. So let's just write this out so far. We have 109 silver. We know our product is 109 cadmium, which has the atomic number 48. Where our silver has atomic number 47. And we want to recognize that Our atomic numbers between these two reactant differ by unit of one. We go from 47 to 48. So we'll say Z differs by one unit. Specifically, we lose one unit. So we would say it differs by -1. And because we know that we have decreased by one unit, we would say that therefore we likely have undergone a beta particle or beta decay. And so we would recall that the symbol for beta decay corresponds to a atomic number of -1. We have our beta particle represented by an electron e and recall that it has a mass number of zero. And so to complete our reaction, we will see that our second product is going to be a beta particle. So we have a beta particle again represented by an electron with the atomic number negative one and the mass number of zero. And so now we need to make sure that this is balanced. But because we have each of our components are reacting in our products, we can see that our entire equation definitely is balanced. And so for our final answer, we have our complete nuclear equation that is balanced with all of our reactant and products. This is our final answer. I hope everything I reviewed was clear. If you have any questions, leave them down below and I will see everyone in the next practice video.