Calculate the number of moles of solute present in each of the following aqueous solutions: (c) 124.0 g of a solution that is 6.45% glucose (C₆H₁₂O₆) by mass.

Video transcript

Hi everyone here we have a question asking us how many moles of solute are present in a 250.0 g acquis solution composed of 8.15% sucrose by mass. So our mass of our solution Is 250 g. The mass of sucrose is 8.15, Divided by Times 250 0. g And that equals 20. grams of sucrose. So our molar mass of sucrose Equals our mass of carbon, which is 12.01 g per mole times 12 Plus our massive hydrogen, which is 1. times 22 Plus our massive oxygen, which is 16. times 11, Which equals .296 g per mole. So our moles of sucrose is .375 g of sucrose times one mole. A sucrose divided by our molar mass, Which we calculated to be 342.296. And our grams are canceling out here And that equals 0. moles. And that is our final answer. Thank you for watching. Bye.