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Ch.11 - Liquids and Intermolecular Forces
Chapter 11, Problem 86a

The following table gives the vapor pressure of hexafluorobenzene (C6F6) as a function of temperature: (a) By plotting these data in a suitable fashion, determine whether the Clausius–Clapeyron equation (Equation 11.1) is obeyed. If it is obeyed, use your plot to determine ∆Hvap for C6F6.

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1. The Clausius-Clapeyron equation is a logarithmic equation that relates the vapor pressure of a substance at a particular temperature to its heat of vaporization. The equation is given as: ln(P) = -ΔHvap/R(1/T) + C, where P is the vapor pressure, ΔHvap is the heat of vaporization, R is the gas constant, T is the temperature in Kelvin, and C is a constant.
2. To determine whether the Clausius-Clapeyron equation is obeyed, plot the natural logarithm of the vapor pressure (ln(P)) against the inverse of the temperature (1/T). If the Clausius-Clapeyron equation is obeyed, the plot should be a straight line.
3. If the plot is a straight line, the Clausius-Clapeyron equation is obeyed. The slope of the line is equal to -ΔHvap/R. Therefore, you can calculate ΔHvap by multiplying the slope by -R.
4. To find the slope, choose two points on the line and use the formula (y2 - y1) / (x2 - x1). Remember that y corresponds to ln(P) and x corresponds to 1/T.
5. Once you have the slope, multiply it by -R to find ΔHvap. Remember to use the appropriate value for R (8.314 J/(mol·K) if your pressure is in atmospheres, or 0.0821 L·atm/(mol·K) if your pressure is in pascals).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Vapor Pressure

Vapor pressure is the pressure exerted by a vapor in equilibrium with its liquid or solid phase at a given temperature. It reflects the tendency of particles to escape from the liquid or solid state into the gas phase. Understanding vapor pressure is crucial for analyzing phase changes and the behavior of substances under varying temperatures.
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Clausius–Clapeyron Equation

The Clausius–Clapeyron equation describes the relationship between vapor pressure and temperature for a substance undergoing phase changes. It is expressed as ln(P2/P1) = -ΔH_vap/R(1/T2 - 1/T1), where ΔH_vap is the enthalpy of vaporization, R is the gas constant, and P1 and P2 are the vapor pressures at temperatures T1 and T2. This equation is essential for determining the heat required for vaporization from experimental data.
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Enthalpy of Vaporization (ΔH_vap)

The enthalpy of vaporization (ΔH_vap) is the amount of energy required to convert a unit mass of a liquid into vapor at constant temperature and pressure. It is a critical thermodynamic property that indicates the strength of intermolecular forces in a substance. A higher ΔH_vap suggests stronger interactions among molecules, which affects the substance's vapor pressure and boiling point.
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Related Practice
Textbook Question

Use the normal boiling points propane (C3H8) -42.1 °C butane (C4H10) -0.5 °C pentane (C5H12) 36.1 °C hexane (C6H14) 68.7 °C heptane (C7H16) 98.4 °C to estimate the normal boiling point of octane (C8H18). Explain the trend in the boiling points.

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Textbook Question

(a) When you exercise vigorously, you sweat. How does this help your body cool?

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Textbook Question

(b) A flask of water is connected to a vacuum pump. A few moments after the pump is turned on, the water begins to boil. After a few minutes, the water begins to freeze. Explain why these processes occur.

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Textbook Question

Suppose the vapor pressure of a substance is measured at two different temperatures.

a. By using the Clausius–Clapeyron equation (Equation 11.1), derive the following relationship between the vapor pressures, 𝑃1 and 𝑃2, and the absolute temperatures at which they were measured, 𝑇1 and 𝑇2:

ln𝑃1𝑃2=−Δ𝐻vap𝑅(1𝑇1−1𝑇2)

b. Gasoline is a mixture of hydrocarbons, a component of which is octane (CH3CH2CH2CH2CH2CH2CH2CH3). Octane has a vapor pressure of 13.95 torr at 25°C and a vapor pressure of 144.78 torr at 75°C. Use these data and the equation in part (a) to calculate the heat of vaporization of octane.

c. By using the equation in part (a) and the data given in part (b), calculate the normal boiling point of octane. Compare your answer to the one you obtained from Exercise 11.83.

d. Calculate the vapor pressure of octane at −30°C.


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Textbook Question

Naphthalene (C10H8) is the main ingredient in traditional mothballs. Its normal melting point is 81 °C, its normal boiling point is 218 °C, and its triple point is 80 °C at 1000 Pa. Using the data, construct a phase diagram for naphthalene, labeling all the regions of your diagram.

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Textbook Question

A particular liquid crystalline substance has the phase diagram shown in the figure. By analogy with the phase diagram for a nonliquid crystalline substance, identify the phase present in each area.

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