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Ch.9 - Molecular Geometry and Bonding Theories

Chapter 9, Problem 77

How would we describe a substance that contains only paired electrons and is weakly repelled by a magnetic field? Which of the following ions would you expect to possess similar characteristics: H2-, Ne2+, F2, O22 +?

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Hello everyone in this video. We're given these ions over here and we're trying to see if they are para magnetic or die magnetic. So just a little refresher that dia magnetic is all is when all of the electrons are being paired us for our para magnetic. That's when at least one electron is unfair. Okay so of course let's go ahead and draw the molecular orbital's for our die atomics. So from age two all the way through and to will have this right here. So that's good to be sigma to p start. Then we'll have our hi to Pete start Then we'll have our Sigma two p. Our pie to pete are sigma to s start kind of scroll down just a little bit. And of course we have our sigma two S And as for 02 through. And you too we'll have our said not to paste er thinner pie two Peaster. Then our Pi two p Our Sigma two p are sigma to start. And lastly our signal to us. Let's be right that a little bit to us. All right. So It has preparing a magnetic it says at least one electron is being compared. So in that case then it means that all the para magnetic ones are going to have an odd number of electrons. And then of course the diet magnetic is going to have an even up. So let's just make it a little bit simple instead of filling these out and we'll know the honor. Even then you can kind of just figure that out without drawing in each of our molecular orbital is here. So first let's go ahead and calculate for our end to then. So RN two plus let's calculate the vents electrons. So each nitrogen atom and we have two of those is going to have five valence electrons because it includes 58, two times 5 is going to be 10. And we have our plus ion here meaning that there's one less electron. So go ahead and actually subtract one electron. Your thing is a total nine electrons. Like I said before, if it's an odd number is going to be parag magnetic. So we'll have this in taro magnetic. Let's go ahead. I like that. It's our first answer. Now, moving on, We'll be working with our 02 two minus. So we have two items of oxygen. Each item will have six bands electrons. The two times 6. That's 18. Of course we have this 2 -6. That means that there's two more electrons. So go ahead to Giving us a total of 20 electrons. 20 is a even number. Just going to be dia magnetic then and again, we'll highlight our answer. Moving on to our 3rd molecule, I have B 2 -. So we have two arms of this be and each adam has three best like drums. So two times 3 is six. Of course we have that minus one charge, meaning that there's one extra electron. Go ahead and add one Giving us to ward off seven electrons. seven is a odd number. So it's going to be impaired magnetic. Alright and again, go ahead and highlight that. Right. Moving down then we'll do the same thing. So now Let's go ahead and work with our C2 plus then. All right. Some each carbon and we have two of those. We'll have four valence electrons Giving us a total of eight electrons. And of course we have to take into consideration the charge that means there's one less electron. So we'll go ahead and subtract one. Giving us a total seven electrons. seven is a odd number is going to be paramedic. And again, we'll highlight that. All right. And lastly, we're going to talk about OF 2 plus. So each flooring item which we have two of has seven valence electrons is in group 78. two times 7 is 14. We have our two plus charge. So there's two less electrons so minus two Secret through 12 electrons. 12 is a even number. So this will be dire magnetic. And that's going to be the last of our problems. And all the ones that highlighted it are going to be our final answers for this problem