Which of the following bonds are polar? (a) C—O, (b) Sl—F, (c) N—Cl, (d) C—Cl. Which is the more electronegative atom in each polar bond?

Video transcript

Hi everyone for this problem. We need to identify if the following bonds are polar and identify the more electro negative atom from the polar bonds. So let's go ahead and get started For something to be polar. It needs to have an electro negativity difference greater than 0.5 and non polar has an electro negativity difference. That is less than 0.5. So we need to calculate the electro negativity difference for each of our bonds to see which one is polar or not. So let's start with our first one. We have sulfur and oxygen. Our electro negativity difference. So for sulfur we have a value of 3.5 for its electro negativity and oxygen has a value of 2.5. So our difference is one and as you can see this is greater than 0.5. So that makes our first one polar. Our first bond is polar and asked to identify the more electro negative atom. So here sulfur is the more electro negative because it has a higher value. Okay let's move on to our second. So we have chlorine and we have flooring. So our electro negativity difference. Our value for chlorine is four And our value for flooring is three. So we have an electro negativity difference of one. And so that makes this bond also polar and the more electro negative is chlorine because it has a higher electro negativity value. Moving on to our next one, we have nitrogen and flooring our electro negativity difference. Our value for nitrogen is for And our value for foreign is three. So our difference is one. So this makes that bond also polar and are more electro negative. Adam is going to be nitrogen. And for our last one we have carbon and hydrogen. Our electoral negativity difference. Our value for carbon is 2.5 and our value for hydrogen is 2.2. So our difference is 0.3. And because this is less than 0.5 that makes this bond non polar and are more electro negative atom here is going to be carbon because it has a higher electro negativity value. So we went ahead and identified the following polar bonds and so one is polar to his polar, three is polar and four is non polar. Okay, so we had three out of the four that were polar. And we identified the more electro negative atoms for all of them. That's the end of this problem. I hope this was helpful.