Skip to main content
Ch.8 - Basic Concepts of Chemical Bonding

Chapter 8, Problem 62

For Group 13–17 elements in the third row of the periodic table and beyond, the octet rule is often not obeyed. A friend of yours says this is because these heavier elements are more likely to make double or triple bonds. Another friend of yours says that this is because the heavier elements are larger and can make bonds to more than four atoms at a time. Which friend is more correct?

Verified Solution
Video duration:
3m
This video solution was recommended by our tutors as helpful for the problem above.
783
views
Was this helpful?

Video transcript

Welcome back everyone. We're told that the octet rule is often disobeyed by elements in the third row and beyond of the periodic table. And which of the below statement explains this statement reads at a heavier element attracts more electrons. We want to recall electron affinity which is the energy of attracted electrons to an atom. And if we think of our trend on our product on our periodic tables, we would recall that electron affinity increases as we go from the left to the top right of our periodic table. So it's increasing as a trend on the periodic table. Now, when it comes to heavier elements or heavier atoms, we recall that are larger atoms with more mass go further down on our periodic table. So we get to larger atoms as we go down our periodic tables. And so that would not correspond to having a increase in electron affinity. That would actually be a decrease in electron affinity since we have heavier atoms. And that is because that is opposite to our trend of increasing electron affinity, which increases as you go up the periodic table. So we would say that statement A is ruled out as a false choice because it does not explain our octet rule. So moving onto choice B, it says that a heavier element is more likely to form double or triple bonds. And we want to recall that not all heavy elements will favor forming double or triple bonds. So this is going to be false because it's just simply not always true. So we can roll choice be out. And lastly we have choice C, which reads a heavier element can make bonds to more than four atoms. And we can recall that elements in period three and below have larger atomic radius and therefore more space and available orbital's to accommodate more electrons. And we should recall that these sorts of elements also will experience less destabilization from additional electron electron repulsion. And we can recall our trend on our periodic table of atomic radius, which is increasing as we go towards the bottom left of our periodic table. So this is with regards to atomic radius. And this trend was in regards to electron affinity. So if we have more space and more available orbital's to accommodate more electrons, it would make sense that heavier elements can make bonds to more than four atoms. And that is why we can say that choice C. Is true, and that would be the explanation for why the octet rule is often disobeyed by period three elements and below. So C is our final answer. I hope everything I reviewed was clear. If you have any questions, leave them down below and I'll see everyone in the next practice video
Related Practice
Textbook Question

Mothballs are composed of naphthalene, C10H8, a molecule that consists of two six-membered rings of carbon fused along an edge, as shown in this incomplete Lewis structure:

(b) Do you expect the C—C bond lengths in the molecule to be similar to those of C—C single bonds, C ═ C double bonds, or intermediate between C—C single and C ═ C double bonds?

559
views
Textbook Question

Mothballs are composed of naphthalene, C10H8, a molecule that consists of two six-membered rings of carbon fused along an edge, as shown in this incomplete Lewis structure:

(c) Not all of the C—C bond lengths in naphthalene are equivalent. Based on your resonance structures, how many C—C bonds in the molecule do you expect to be shorter than the others?

976
views
Textbook Question

(b) Which of these compounds or ions is an exception to the octet rule: borohydride (BH4-), borazine (B3N3H6, which is analogous to benzene with alternating B and N in the ring), or boron trichloride?

974
views
Textbook Question

Draw the Lewis structures for each of the following molecules or ions. Identify instances where the octet rule is not obeyed; state which atom in each compound does not follow the octet rule; and state how many electrons surround these atoms: (a) PF6-, (b) BeCl2, (c) NH3, (d) XeF2O (the Xe is the central atom), (e) SO42- .

1336
views
Textbook Question

In the vapor phase, BeCl2 exists as a discrete molecule. (a) Draw the Lewis structure of this molecule, using only single bonds. Does this Lewis structure satisfy the octet rule?

611
views
Textbook Question

In the vapor phase, BeCl2 exists as a discrete molecule. (c) On the basis of the formal charges, which Lewis structure is expected to be dominant for BeCl2?

807
views