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Ch.5 - Thermochemistry
Chapter 5, Problem 111

From the following data for three prospective fuels, calculate which could provide the most energy per unit mass and per unit volume:

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Energy Density

Energy density refers to the amount of energy stored in a given system or region of space per unit volume or mass. It is a crucial concept in evaluating fuels, as it determines how much energy can be extracted from a specific quantity of fuel. Higher energy density means that less fuel is needed to produce the same amount of energy, making it more efficient for applications like transportation.
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Calorimetry

Calorimetry is the science of measuring the heat of chemical reactions or physical changes. In the context of fuels, calorimetry helps determine the heat of combustion, which is the energy released when a fuel is burned. Understanding calorimetry allows for the comparison of different fuels based on their energy output, which is essential for identifying the most efficient fuel.
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Specific Energy vs. Volumetric Energy Density

Specific energy is the amount of energy per unit mass of fuel, while volumetric energy density is the amount of energy per unit volume. These two metrics are important for evaluating fuels in different contexts; for instance, specific energy is critical for weight-sensitive applications like aviation, whereas volumetric energy density is more relevant for storage and transportation considerations. Analyzing both helps in making informed decisions about fuel selection.
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Related Practice
Textbook Question

A coffee-cup calorimeter of the type shown in Figure 5.18 contains 150.0 g of water at 25.1°C A 121.0-g block of copper metal is heated to 100.4°C by putting it in a beaker of boiling water. The specific heat of Cu(s) is 0.385 J/g-K The Cu is added to the calorimeter, and after a time the contents of the cup reach a constant temperature of 30.1°C (d) What would be the final temperature of the system if all the heat lost by the copper block were absorbed by the water in the calorimeter?

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Textbook Question

(b) Assuming that there is an uncertainty of 0.002 °C in each temperature reading and that the masses of samples are measured to 0.001 g, what is the estimated uncertainty in the value calculated for the heat of combustion per mole of caffeine?

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Textbook Question

We can use Hess's law to calculate enthalpy changes that cannot be measured. One such reaction is the conversion of methane to ethane: 2 CH4(g) → C2H6(g) + H2(g) Calculate the ΔH° for this reaction using the following thermochemical data: CH4(g) + 2 O2(g) → CO2(g) + 2 H2O(l) ΔH° = -890.3 kJ 2 H2(g) + O2(g) → 2 H2O(l) H° = -571.6 kJ 2 C2H6(g) + 7 O2(g) → 4 CO2(g) + 6 H2O(l) ΔH° = -3120.8 kJ

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Textbook Question
When magnesium metal is burned in air (Figure 3.6), two products are produced. One is magnesium oxide, MgO. The other is the product of the reaction of Mg with molecular nitrogen, magnesium nitride. When water is added to magnesium nitride, it reacts to form magnesium oxide and ammonia gas. (e) The standard enthalpy of formation of solid magnesium nitride is -461.08 kJ>mol. Calculate the standard enthalpy change for the reaction between magnesium metal and ammonia gas.
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Textbook Question

A 201-lb man decides to add to his exercise routine by walking up three flights of stairs (45 ft) 20 times per day. Hefigures that theworkrequired to increasehis potential energy in this way will permit him to eat an extra order of French fries, at 245 Cal, without adding to his weight. Is he correct in this assumption?

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Textbook Question

Sucrose (C12H22O11) is produced by plants as follows: 12 CO2(g) + 11 H2O(l) → C12H22O11 + 12 O2(g) H = 5645 kJ About 4.8 g of sucrose is produced per day per square meter of the earth's surface. The energy for this endothermic reaction is supplied by the sunlight. About 0.1 % of the sunlight that reaches the earth is used to produce sucrose. Calculate the total energy the sun supplies for each square meter of surface area. Give your answer in kilowatts per square meter 1kW/m2 where 1W = 1 J/s2.

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