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Ch.5 - Thermochemistry

Chapter 5, Problem 76

Calcium carbide (CaC2) reacts with water to form acetylene (C2H2) and Ca(OH)2. From the following enthalpy of reaction data and data in Appendix C, calculate H°f for CaC2(s): CaC2(s) + 2 H2O(l) → Ca(OH2)(s) + C2H2(g) ΔH° = -127.2 kJ

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Hello. Everyone in this video, we're trying to calculate the standard entropy of formation for beautiful. So C. Four H. 90. H. And it's given that the complete combustion of one mole of vinyl releases this much heat. Alright, so we have a equation to use for calculating the standard and Topia formation and that's going to be let's spread this in black. So the delta H of a reaction is going to equal to the delta H. Affirmation of the products minus the delta age formation of erect. It's alright so here are some of the values that I'm going to be using to do this here. These products can also be provided to you by your professor or even given to you in your textbook. So I'll have that the delta H formation For c. 0. 2. Guess It's going to equal to negative 393.5 kila jules per Permal. And then my delta age information For my H 20 liquid. It's going to equal to negative 285. killer jewels, more lassie, my delta H affirmation of 02. It is going to be gas Is going to equal to zero. And let's not forget we also have this value right here. Alright, so now using this equation right over here we can continue and do our plug in the values to find the standard entropy of formation. And so let's do this in purple. So my delta age of reaction is given to us. Right so again, I'm just going to go ahead and rewrite this equation and so will have The value given to us in the problem as 0.45 killer jewels. And because we're if we go back to the problem just a little bit, it's saying that we're releasing this amount of heat when we're releasing this amount of heat that's going to be a negative charge or a negative sign. And so continuing on now, we have the delta age for our products. If you go back to the equation, the products, we have four moles of C. 02 and five moles of H 20. So we'll start off with the c. 0. 2. And so we have this value over here. So you have negative 393.5. And we're going to multiply this by four because we have four moles of the C. 02. And then we're gonna add this by the delta H. S. Of our H. 20. Which we have right over here. So we have negative 285. Times five for the five moles of H. 20. And then we're gonna go ahead and subtract this by all the delta H. Of formation of the reactors. And so we don't know what the delta age information for our C. four h. 90. H. But we do have the delta age affirmation for the 02. So put the delta H information for the C. Four H. 90. H. As an X. And then we'll have that to be multiplying. But it's pretty dark. So it gets this confusing times one And then we're adding zero. And this one right here is just because we have one more and then zero because six moles times zero is just zero. Now putting all this into my calculator to solve for my ex, we'll get that the X. Is going to equal to - 0.3 killer jules Permal. And again, just to replace the X. We said that the X. Is going to equal to the delta H. Of formation of our c. four age nine O. H. Compound. And it's again equal to negative 327.3 killer jewels Permal. And this is going to be my final answer for this question.
Related Practice
Textbook Question

Acetylene (C2H2(g)) is used for welding because oxyacetylene is the hottest burning common fuel gas. Using standard enthalpies of formation, calculate the quantity of heat produced when 10 g of acetylene is completely combusted in air under standard conditions.

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Textbook Question

Using values from Appendix C, calculate the value of H for each of the following reactions: (a) CaO(s) + 2 HF(g) → CaF2(s) + H2O(g)

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Textbook Question

Complete combustion of 1 mol of acetone (C3H6O) liberates 1790 kJ: C3H6O(l) + 4 O2(g) → 3 CO2(g) + 3 H2O(l) ΔH° = -1790 kJ Using this information together with the standard enthalpies of formation of O2(g), CO2(g), and H2O(l) from Appendix C, calculate the standard enthalpy of formation of acetone.

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Textbook Question

Gasoline is composed primarily of hydrocarbons, including many with eight carbon atoms, called octanes. One of the cleanest–burning octanes is a compound called 2,3,4- trimethylpentane, which has the following structural formula: The complete combustion of one mole of this compound to CO2(g) and H2O(g) leads to ΔH° = -5064.9 kJ. (b) By using the information in this problem and data in Table 5.3, calculate H°f for 2,3,4-trimethylpentane.

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Textbook Question

Diethyl ether, C4H10O(l), a flammable compound that was once used as a surgical anesthetic, has the structure The complete combustion of 1 mol of C4H10O(l) to CO2(g) and H2O(l) yields ΔH° = -2723.7 kJ. (a) Write a balanced equation for the combustion of 1 mol of C4H10O(l).

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Textbook Question

Ethanol (C2H5OH) is blended with gasoline as an automobile fuel. (c) Calculate the heat produced per liter of ethanol by combustion of ethanol under constant pressure. Ethanol has a density of 0.789 g/mL.

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