Calicheamicin gamma-1, C55H74IN3O21S4, is one of the most potent antibiotics known: one molecule kills one bacterial cell. Describe how you would (carefully!) prepare 25.00 mL of an aqueous calicheamicin gamma-1 solution that could kill 1.0 * 108 bacteria, starting from a 5.00 * 10-9M stock solution of the antibiotic.
Ch.4 - Reactions in Aqueous Solution
Chapter 4, Problem 81b
(b) What volume of HCl is needed to neutralize 2.87 g of Mg(OH)2?
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Neutralization Reaction
A neutralization reaction occurs when an acid reacts with a base to produce water and a salt. In this case, hydrochloric acid (HCl) reacts with magnesium hydroxide (Mg(OH)2) to form magnesium chloride (MgCl2) and water. Understanding this reaction is crucial for determining the stoichiometry involved in calculating the required volume of HCl.
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Stoichiometry
Stoichiometry is the calculation of reactants and products in chemical reactions based on balanced chemical equations. It allows us to determine the mole ratios of the substances involved. For this question, knowing the molar mass of Mg(OH)2 and the balanced equation for its reaction with HCl will enable us to find out how much HCl is needed to neutralize a specific mass of Mg(OH)2.
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Molarity
Molarity is a measure of concentration defined as the number of moles of solute per liter of solution. It is essential for calculating the volume of HCl required for neutralization. By knowing the molarity of the HCl solution, we can use the stoichiometric relationships from the balanced equation to find the exact volume needed to react with the given mass of Mg(OH)2.
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Pure acetic acid, known as glacial acetic acid, is a liquid with a density of 1.049 g/mL at 25 C. Calculate the molarity of a solution of acetic acid made by dissolving 20.00 mL of glacial acetic acid at 25 C in enough water to make 250.0 mL of solution.
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(a) What volume of 0.115 M HClO4 solution is needed to neutralize 50.00 mL of 0.0875 M NaOH?
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(d) If 45.3 mL of a 0.108 M HCl solution is needed to neutralize a solution of KOH, how many grams of KOH must be present in the solution?
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(a) How many milliliters of 0.120 M HCl are needed to completely neutralize 50.0 mL of 0.101 M Ba(OH)2 solution?
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(b) How many milliliters of 0.125 M H2SO4 are needed to neutralize 0.200 g of NaOH?
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