Skip to main content
Ch.3 - Chemical Reactions and Reaction Stoichiometry
Chapter 3, Problem 86

When hydrogen sulfide gas is bubbled into a solution of sodium hydroxide, the reaction forms sodium sulfide and water. How many grams of sodium sulfide are formed if 1.25 g of hydrogen sulfide is bubbled into a solution containing 2.00 g of sodium hydroxide, assuming that the sodium sulfide is made in 92.0% yield?

Verified step by step guidance
1
First, write down the balanced chemical equation for the reaction. Hydrogen sulfide (H2S) reacts with sodium hydroxide (NaOH) to form sodium sulfide (Na2S) and water (H2O). The balanced equation is: 2NaOH + H2S -> Na2S + 2H2O
Next, calculate the number of moles of H2S and NaOH using their respective molar masses. The molar mass of H2S is approximately 34.08 g/mol and the molar mass of NaOH is approximately 40.00 g/mol. Use the formula: number of moles = mass / molar mass.
Then, determine the limiting reactant. This is the reactant that will be completely consumed first in the reaction. Compare the mole ratio of H2S to NaOH in the balanced equation with the ratio of the number of moles you calculated in the previous step.
Once you have identified the limiting reactant, you can calculate the theoretical yield of Na2S. This is the maximum amount of Na2S that can be produced from the limiting reactant. Use the stoichiometry of the balanced equation to do this.
Finally, calculate the actual yield of Na2S using the percent yield given in the problem. The actual yield is the amount of product that is actually formed in a reaction. It is given by the formula: actual yield = theoretical yield * (percent yield / 100).

Verified Solution

Video duration:
3m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Stoichiometry

Stoichiometry is the calculation of reactants and products in chemical reactions based on the balanced chemical equation. It allows us to determine the amount of product formed from a given amount of reactant by using mole ratios derived from the coefficients in the balanced equation.
Recommended video:
Guided course
01:16
Stoichiometry Concept

Percent Yield

Percent yield is a measure of the efficiency of a chemical reaction, calculated as the ratio of the actual yield to the theoretical yield, multiplied by 100. It indicates how much of the expected product was actually obtained, which is crucial for understanding the effectiveness of the reaction under given conditions.
Recommended video:
Guided course
03:09
Percent Yield in Reactions

Limiting Reactant

The limiting reactant is the substance that is completely consumed first in a chemical reaction, thus determining the maximum amount of product that can be formed. Identifying the limiting reactant is essential for accurate stoichiometric calculations, as it dictates the extent of the reaction and the yield of the product.
Recommended video:
Guided course
01:30
Limiting Reagent Concept
Related Practice
Textbook Question

When benzene 1C6H62 reacts with bromine 1Br22, bromobenzene 1C6H5Br2 is obtained: C6H6 + Br2¡C6H5Br + HBr (b) If the actual yield of bromobenzene is 42.3 g, what is the percentage yield?

740
views
1
rank
Textbook Question

When ethane 1C2H62 reacts with chlorine 1Cl22, the main product is C2H5Cl, but other products containing Cl, such as C2H4Cl2, are also obtained in small quantities. The formation of these other products reduces the yield of C2H5Cl. (a) Calculate the theoretical yield of C2H5Cl when 125 g of C2H6 reacts with 255 g of Cl2, assuming that C2H6 and Cl2 react only to form C2H2Cl and HCl. (b) Calculate the percent yield of C2H5Cl if the reaction produces 206 g of C2H5Cl.

1309
views
Textbook Question

Hydrogen sulfide is an impurity in natural gas that must be removed. One common removal method is called the Claus process, which relies on the reaction: 8 H2S1g2 + 4 O21g2¡S81l2 + 8 H2O1g2 Under optimal conditions the Claus process gives 98% yield of S8 from H2S. If you started with 30.0 g of H2S and 50.0 g of O2, how many grams of S8 would be produced, assuming 98% yield?

1894
views
Textbook Question

Write balanced chemical equations for (a) the complete combustion of acetone (CH3COCH3), a common organic solvent

1076
views
Textbook Question

Write balanced chemical equations for (c) the combination reaction between nickel metal and chlorine gas.

464
views
Textbook Question

If 2.0 mol CH3CH2CH2COOH, 2.0 mol C4H10, and 2.0 mol C6H6 are completely combusted in oxygen, which one produces the largest number of moles of H2O?

451
views