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Ch.3 - Chemical Reactions and Reaction Stoichiometry
Chapter 3, Problem 35a

Calculate the following quantities: (a) mass, in grams, of 0.105 mol sucrose (C12H22O11)

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molar Mass

Molar mass is the mass of one mole of a substance, typically expressed in grams per mole (g/mol). It is calculated by summing the atomic masses of all the atoms in a molecule. For sucrose (C12H22O11), the molar mass can be determined by adding the molar masses of carbon, hydrogen, and oxygen in the given ratio.
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Mole Concept

The mole is a fundamental unit in chemistry that quantifies the amount of substance. One mole contains approximately 6.022 x 10^23 entities (Avogadro's number), which can be atoms, molecules, or ions. Understanding the mole concept is essential for converting between the number of particles and mass, allowing for calculations involving chemical reactions and stoichiometry.
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Mass Calculation

To calculate the mass of a substance from the number of moles, the formula used is: mass (g) = number of moles × molar mass (g/mol). This relationship allows chemists to determine how much of a substance is present in a given number of moles, which is crucial for preparing solutions and conducting reactions in the laboratory.
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