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Ch.3 - Chemical Reactions and Reaction Stoichiometry
Chapter 3, Problem 44a

At least 25 mg of tetrahydrocannabinol (THC), the active ingredient in marijuana, is required to produce intoxication. The molecular formula of THC is C21H30O2. How many moles of THC does this 25 mg represent?

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1
First, convert the mass of THC from milligrams to grams. Since there are 1000 milligrams in a gram, divide 25 mg by 1000 to get the mass in grams.
Next, calculate the molar mass of THC using its molecular formula, C21H30O2. Add up the atomic masses of all the atoms in the formula: 21 carbon atoms, 30 hydrogen atoms, and 2 oxygen atoms.
The atomic masses are approximately: Carbon (C) = 12.01 g/mol, Hydrogen (H) = 1.01 g/mol, and Oxygen (O) = 16.00 g/mol. Multiply each atomic mass by the number of atoms of that element in the formula and sum them to find the molar mass of THC.
Now, use the formula for moles: moles = mass (g) / molar mass (g/mol). Substitute the mass of THC in grams and the molar mass you calculated into this formula.
Finally, solve the equation to find the number of moles of THC that 25 mg represents.

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