Dichloroethylene 1C2H2Cl22 has three forms (isomers), each of which is a different substance. (a) Draw Lewis structures of the three isomers, all of which have a carbon–carbon double bond.

Video transcript

Hello. Everyone in this video we have to draw the lower structures for three summers of die bro mo di chloral ethylene. So its members are the or have the same molecular formula but there's different arrangements in space. So let's go ahead and break down this name of the molecule. So we see that we have an at the end We have an 18 right over here. So I mean is a two carbon double bound and we see a dye bromo. So dye bromo means we have to remain atoms and the middle section we have dyke loro. That means we have two chlorine atoms. So let's go ahead and draw this out. Of course our carbons are going to be our central atoms and it's double bound to another carbon and then we have four possible we'll just call it connecting atoms. We have to bro means and to chlorine. So one possible configuration would be that the left side will contain our bro means. And then the rights I can contain our chlorine and just basing off our other two sms on this one, you can go ahead and draw out the rest. So one could be again, we have our carbon carbon double bound and then on the right side we switch it up, we're gonna have a chlorine and a brewing. Another possibility is again, if we have the chlorine chlorine or the carbon carbon double bound and then maybe the bottom would have the chlorine and then on the top we have our bro means. So as long as the molecular formula is the same and there's a different arrangement in space, then it's going to be a possible member of dye bromo dyke loro. So these three structures here are going to be my final answer for this problem. Thank you all so much for watching.