Skip to main content
Ch.23 - Transition Metals and Coordination Chemistry
Chapter 23, Problem 91a,d

The coordination complex [Cr(CO)6] forms colorless, diamagnetic crystals that melt at 90 °C
a. What is the oxidation number of chromium in this compound?
d. Write the name for [Cr(CO)6] using the nomenclature rules for coordination compounds.

Verified step by step guidance
1
Identify the ligands in the coordination complex. In [Cr(CO)6], the ligand is carbon monoxide (CO), which is a neutral ligand.
Determine the charge of the ligands. Since CO is a neutral ligand, it contributes a charge of 0 to the complex.
Calculate the overall charge of the complex. [Cr(CO)6] is a neutral complex, meaning the sum of the oxidation state of chromium and the charges of the ligands is zero.
Set up the equation for the oxidation state of chromium. Let x be the oxidation state of chromium. Since the complex is neutral and CO is neutral, the equation is x + 6(0) = 0.
Solve for x to find the oxidation state of chromium. Since the equation simplifies to x = 0, the oxidation state of chromium in [Cr(CO)6] is 0. The name of the compound is hexacarbonylchromium(0).

Verified Solution

Video duration:
0m:0s
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?