Write balanced equations for each of the following reactions.

e. Potassium peroxide reacts with CO₂(g) to give potassium carbonate and O₂.

Video transcript

Hello, everyone. Today we have the following problem. Write a balanced equation for the reaction of sodium peroxide with carbon dioxide gas to form sodium carbonate and oxygen. So if we write this reaction out sodium peroxide as the following formula and it tastes solid, we then react that with carbon dioxide gas. And this forms the following is this forms the products known as sodium carbonate. So we have our sodium Urban eight which is also a solid and then we form oxygen gas or 02. Now to balance this out, we want first write out all the atoms that are present between the between this reaction we want to count them on. Then how many there are on both sides the reactions and products? So sodium, there are two moles of sodium on the left and two on the right, there's four moles of oxygen on the left and there's five moles of oxygen on the right. And for carbon, there's one on each side. So usually when balancing equations, we want to start with carbon atoms, however, the carbon atoms are already bounced. So we will start with oxygen between four and five. We need to find a common denominator. And so, if we multiply the carbon dioxide by coefficient of two, we will essentially go from four moles of oxygen to six. And we will also increase the number of carbon atoms, we have to two. So now we have an unbalanced amount of carbon atoms. And so now we can focus on the carbon atoms to get from 1 to 2. On the right side, we need to multiply by a coefficient of two. We will do that to our sodium carbonate. This not only changes the number of carbon atoms to two, but it changes the number of sodium atoms on the right to four. And it changed the number of oxygen atoms 28. For oxygen, we have the two times the three coefficients for six and then the oxygen gas for two more. So eight and all that's left is to balance the sodium and the oxygens, let's balance both at the same time. So if we add two to our reactant side on the sodium peroxide, we will increase the number of sodium atoms to four and the number of oxygen atoms will increase two times the two for the oxygen and our sodium peroxide for four. And then we have two molecules of oxygen in that carbon dioxide. And we have two of those. So that's four. So four plus four gives us eight. And so with that, we actually have the balanced equation and the oxygen gas gets a coefficient of one, but we don't really draw that in. And so with that, we have solved the problem overall, I hope is helped. And until next time.