Skip to main content
Pearson+ LogoPearson+ Logo
Ch.20 - Electrochemistry
All textbooksBrown 14th EditionCh.20 - ElectrochemistryProblem 106b
Previous problem
Next problem

Chapter 20, Problem 106b

Disulfides are compounds that have S ¬ S bonds, like peroxides have O ¬ O bonds. Thiols are organic compounds that have the general formula R ¬ SH, where R is a generic hydrocarbon. The SH- ion is the sulfur counterpart of hydroxide, OH-. Two thiols can react to make a disulfide, R ¬ S ¬ S ¬ R. (b) What is the oxidation state of sulfur in a disulfide?

Verified Solution
Video duration:
1m
This video solution was recommended by our tutors as helpful for the problem above.
Was this helpful?

Video transcript

Hi everyone here we have the oxidation number of oxygen, which is almost always negative too. But there are a few exceptions, such as peroxide, where the oxidation number is negative one and another exception is oxy fluoride. Were asked to identify the oxidation number of oxygen and oxy fluoride. The flooring Is in group seven on the periodic table. An element in Group seven have an oxidation number of negative one. So it's gonna have an oxidation number of negative one. For the oxidation state, oxy fluoride, it's gonna be equal to the oxidation state of oxygen Plus two oxidation state of Florence because we have two florin in the compound, the oxidation state oxy fluoride Is zero because it is a neutral compound because it has no charge. An oxidation state of Florence is negative one. We're gonna have zero because oxidation state of oxygen Plus two times negative one we're gonna have zero. It was also a state of oxygen -2. And if we add two to both sides, the oxidation state of oxygen We get plus two. Thanks for watching my video and I hope it was helpful
Previous problem
Next problem
Related Practice
Textbook Question

A voltaic cell is constructed that uses the following half-cell reactions: Cu+1aq2 + e- ¡ Cu1s2 I21s2 + 2 e- ¡ 2 I-1aq2 The cell is operated at 298 K with 3Cu+4 = 0.25 M and 3I-4 = 0.035 M. (a) Determine E for the cell at these concentrations.

2755
views
1
rank
Textbook Question
(b) Given the following reduction potentials, calculate the standard emf of the cell: Cd1OH221s2 + 2 e- ¡ Cd1s2 + 2 OH-1aq2 E°red = -0.76 V NiO1OH21s2 + H2O1l2 + e- ¡ Ni1OH221s2 + OH-1aq2 E°red = +0.49 V
1395
views
Textbook Question

The capacity of batteries such as the typical AA alkaline battery is expressed in units of milliamp-hours (mAh). An AA alkaline battery yields a nominal capacity of 2850 mAh. (b) The starting voltage of a fresh alkaline battery is 1.55 V. The voltage decreases during discharge and is 0.80 V when the battery has delivered its rated capacity. If we assume that the voltage declines linearly as current is withdrawn, estimate the total maximum electrical work the battery could perform during discharge.

9695
views
Textbook Question

Disulfides are compounds that have S ¬ S bonds, like peroxides have O ¬ O bonds. Thiols are organic compounds that have the general formula R ¬ SH, where R is a generic hydrocarbon. The SH- ion is the sulfur counterpart of hydroxide, OH-. Two thiols can react to make a disulfide, R ¬ S ¬ S ¬ R. (c) If you react two thiols to make a disulfide, are you oxidizing or reducing the thiols?

448
views
Textbook Question

Calculate the number of kilowatt-hours of electricity required to produce 1.0 * 103 kg (1 metric ton) of aluminum by electrolysis of Al3+ if the applied voltage is 4.50 V and the process is 45% efficient.

980
views
Textbook Question

The Haber process is the principal industrial route for converting nitrogen into ammonia: N2(g) + 3 H2(g) → 2 NH3(g) (b) Using the thermodynamic data in Appendix C, calculate the equilibrium constant for the process at room temperature.

717
views