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Ch.2 - Atoms, Molecules, and Ions

Chapter 2, Problem 73g

Write the chemical formulas for the following compounds: (g) sodium hypobromite.

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Hello everyone today. We are being given the falling problem, which chemical formula corresponds to rubidium oxalate. So the first thing we need to do is we need to take into account what each of these would look like and what their charges would be. So we have rubidium which has a symbol of our B. And it is a group one, A element and therefore has a positive one charge. So this is going to be rubidium positive one. We're going to make note of our oxalate And it is a poly atomic ion with a symbol of two carbons For oxygen's in an overall -2 charge. And so what we need to do is we need to crisscross the charges and that would be their subscript in the chemical formula. So we would have our rubidium with a positive charge. We would have our oxalate here With our -2 charge. And we essentially crisscrossed their charges. To give us the answer of rubidium to there would be to write their charges become their subscript. And then we would have the oxalate here with no subscript because the charge everybody in was one. And so this answer choice is going to best be represented by answer choice. A and with that we have answered the question overall. I do hope this helped. And until next time