Consider the following organic substances: ethylethanoate, ethylmethylether, hexanol, and propanone. (b) Which of these molecules contain a C = O group?

Question

Accepted Answer

hey everyone in this example we need to determine which of the given molecules contains a carbon carbon nail group. For our first molecule were given methyl metha No wait, we're going to recall that to draw this molecule out, we have a carbondale where we have an oxygen double bonded to a carbon atom and this carbon atom is bonded to a hydrogen and also bonded to another atom. Where in this case because we have the atom method. Wait, we have an oxygen, a second oxygen atom here bonded to a Metal Ch three Group. So we don't really need to draw in this fourth hydrogen because it's interpreted that it's there. So recall that for carbon to be stable it should be bonded to four bonds. So right now it has 123 bonds. And then we would understand that there's an invisible hydrogen atom that is bonded to this carbon here. So this is our molecule metal And sorry, there's no dash there. So it's metal method. No wait. So moving on to the next molecule were given were given one a foxy butane. So to draw this molecule out, We have a methyl group CH three bonded to a carbon where at our second carbon here, we have a bond to an oxygen atom because that is our first substitue in And because we have the ending butane that tells us that we have four carbons in this molecule. So we're going to make former bonds of carbon to the oxygen atom here. So we have one, 234. So we can fill in our methyl groups and this is our molecule one with oxy butane. Moving on to our next molecule were given the molecule one prop in all. So to draw that molecule we have a hydroxide group O. H. And just to be clear, the oxygen is on the bond here which is bonded to a carbon atom. That is then bonded to another carbon atom here. Where we end off with a methyl group. And this is our one probe in all where our substitue in being our hydroxide or alcohol group was bonded to our first carbon because we always want our substitutes to be bonded to the lowest numbered carbon. And because we have the prefix probe, we correctly drew in three carbon atoms in our molecule and last we have our compound to Penton on. So to draw that out, we're going to have a carbonell group bonded to our second carbon atom here. So we'll draw the carbondale group where we have the carbon atom number two here and we have a metal group here. We have our second carbon atom here bonded to double bonded to an oxygen where it's bonded to another carbon atom. So we're going to continue our molecule here. And because we have the prefix spent, we should recall that pent tells us we have five carbon atoms. So we are going to form two more bonds to carbon. To complete this molecule. So right now counting up our carbons, we have a total of 1234 and then five here, Which is our molecule for two pentagon. So we should recognize by now after drawing these molecules that a carbon eel group appears where we have a carbon atom double bonded to an oxygen, where that carbon is bonded to two other carbon chains. Or we can say our groups. And so looking at our molecules above, we can see that we have a carbon here double bonded to an oxygen where we have this carbon also bonded to two other carbon chains. We have one carbon chain here and our second carbon chain here is our methyl group. And so we would say that this section of our molecule is our Carbonell. Moving on to the next molecule that had a carbondale group. Looking at our method method. Oh wait, we have another carbonell group where we have this carbon brought it to a double bonded to an oxygen, brought it to a hydrogen as well as bought it to this carbon chain over here. And so this would be our other carbonell group. And so to complete this example, we would say that therefore metal method await and to Penton on contain carbon nails. So these two molecules will be our final answers that contain carbon. You'll groups in their structures. So I hope that everything I went through is clear. If you have any questions, please leave them down below and I will see everyone in the next practice video.

Consider the following organic substances: ethylethanoate, ethylmethylether, hexanol, and propanone. (b) Which of these molecules contain a C = O group?

Verified Solution

Key Concepts

Functional Groups

Carbonyl Group

Molecular Structure and Nomenclature