Calculate the solubility of LaF3 in grams per liter in (a) pure water.

Video transcript

Hello. In this problem we are asked to determine the scalability of business three I'd I'd given the scalability product constant and pure water. And report our answer in grams per leader. Let's begin by writing the equation. Then that describes equilibrium between are solid and it's science. So we have business three I died associates and to form business three And three moles of I died. So the more solid ability has to do with business three I died for every one mole of business three I died that associates. We get one mold. Business three and three moles of died. So that's three S are solid ability product constant expression then is equal to the concentration of business Lions times the concentration of iodide ions cubed. Which comes from the coefficient in the balanced reaction equation are pure solid. Does not appear in the equilibrium cost expression. This then works out to S times three S cubed. This then is equal to 27 as to the fourth we're told this is equal to then 7.71 times 10 to the minus 19. So we solve for the Mueller scalability, We take the viable sides by and then take the fourth root or raise it to the 1/4 power. Our moral responsibility then works out to 1.30 times 10 to the minus five. We were asked to report this liability in terms of grams per liter. So we'll take our Mueller scalability and convert our molds of Business three I died two g. Using a smaller mass. one mole of business three I died has a mass of .694 grams Are moles of business three. iodide cancels and we're left with. The scalability, then is equal to 7.67 Times 10 to the -3 g of business three I died per leader. This scalability then corresponds to answer a thanks for watching. Hope. This helped.