A solution is made containing 20.8 g of phenol (C₆H₅OH) in 425 g of ethanol (CH₃CH₂OH). Calculate (c) the molality of phenol.

Video transcript

Hi everyone here we have a question telling us that a solution contains 19.3 g of tall ewing and 564 g of benzene. And our goal is to calculate the concentration of benzene in terms of morality. So there's fewer amount of our tall ewing, which makes it our solid. So now we need to calculate the moles of valuing our molar mass. A tall ewing equals 92 0. grams per mole. So 19 0. g times one mole, Divided by 92. g. Our g will cancel out and that will equal 0.21 mold of tall ewing. And now we can calculate our morality. So morality equals models divided by kilograms. So let's take our 64g of Benzene And change it to kg. So we'll do times one kilogram Divided by 1000 g. And our g will cancel out. And that will equal 0. kg. So our morality Is going to equal 0.21 moles. That's all you mean, divided by 0. kilograms. A Benzene Which equals 0.371 morality. And that is our final answer. Thank you for watching. Bye