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Ch.10 - Gases

Chapter 10, Problem 90

The planet Jupiter has a surface temperature of 140 K and a mass 318 times that of Earth. Mercury (the planet) has a surface temperature between 600 K and 700 K and a mass 0.05 times that of Earth. On which planet is the atmosphere more likely to obey the ideal-gas law? Explain.

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Hey everyone in this example, we need to identify the planet below where the gasses are more likely to behave ideally. So we want to recall what behaving ideally as a gas really means and we would recall that that corresponds to having ideal behavior at high temperatures and low pressures. We also want to recall that the lower the mass of something that will correspond to a lower pressure. So looking at the information of our given planets to consider, we have either venus or we have Neptune, we're told that venus has a surface temperature of 7 37 kelvin, which is a pretty high temperature and it has a mass that is 370.815 times that of earth Moving on to Neptune, we have a much lower temperature at 73 Kelvin with a mass that is 17.1 times that of Earth. So it has a much larger mass than our massive earth and also much larger than Venus. So again, as we stated, ideal behavior of a gas would occur at high temperature, which we do have on venus at 7 37 kelvin and low pressure. And we would have low pressure because our mass for venus is much lower in comparison to Neptune's mass. And so that means venus would be the planet where we would have ideal behavior of gasses occur. So, a is our final answer. If you have any questions, please leave them down below and I will see everyone in the next practice video
Related Practice
Textbook Question

Arsenic(III) sulfide sublimes readily, even below its melting point of 320 °C. The molecules of the vapor phase are found to effuse through a tiny hole at 0.52 times the rate of effusion of Xe atoms under the same conditions of temperature and pressure. What is the molecular formula of arsenic(III) sulfide in the gas phase?

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Textbook Question

A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 105 s for 1.0 L of the gas to effuse. Under identical experimental conditions it required 31 s for 1.0 L of O2 gas to effuse. Calculate the molar mass of the unknown gas. (Remember that the faster the rate of effusion, the shorter the time required for effusion of 1.0 L; in other words, rate is the amount that diffuses over the time it takes to diffuse.)

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Textbook Question

(b) List two reasons why the gases deviate from ideal behavior.

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Textbook Question

Which statement concerning the van der Waals constants a and b is true? (a) The magnitude of a relates to molecular volume, whereas b relates to attractions between molecules. (b) The magnitude of a relates to attractions between molecules, whereas b relates to molecular volume. (c) The magnitudes of a and b depend on pressure. (d) The magnitudes of a and b depend on temperature.

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Textbook Question
Based on their respective van der Waals constants ( Table 10.3), is Ar or CO2 expected to behave more nearly like an ideal gas at high pressures?
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Textbook Question

Calculate the pressure that CCl4 will exert at 80 °C if 1.00 mol occupies 33.3 L, assuming that (a) CCl4 obeys the ideal-gas equation (b) CCl4 obeys the van der Waals equation. (Values for the van der Waals constants are given in Table 10.3.)

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