Consider the following reaction mechanism: 

OCl^–(aq) + H₂O(l) ⇌ HOCl(aq) + OH^–(aq)       (fast equilibrium)

I^–(aq) + HOCl(aq) → HOI(aq) + Cl^–(aq)           (slow)

HOI(aq) + OH^–(aq) → H₂O(l) + OI^–(aq)           (fast)

Determine the catalyst and intermediate(s).

A. No catalyst, intermediate = HOCl, HOI, OH^–

B. No catalyst, intermediates = H₂O, HOCl, HOI, OH^–

C. Catalyst = H₂O, intermediates = HOCl, HOI, OH^–

D. Catalyst = H₂O, intermediate = HOCl, HOI