the-first-order-rate-constant-for-the-decomposition-of-n2o5-2-n2o51g24-no21g2-o2

Question

The first-order rate constant for the decomposition of the hypothetical compound A₂B₅, 2 A₂B₅(g) → 4 AB₂(g) + B₂(g), at 70 °C is 2.34 × 10^-3 s^-1. Suppose we start with 0.01250 mol of A₂B₅(g) in a volume of 1.5 L. How many moles of A₂B₅ will remain after 3.0 min?

Accepted Answer

8.2×10^-3mol

Answer

1.25×10^-3mol

Answer

1.6×10^-3mol

Answer

2.3×10^-2mol

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The first-order rate constant for the decomposition of the hypothetical compound A₂B₅, 2 A₂B₅(g) → 4 AB₂(g) + B₂(g), at 70 °C is 2.34 × 10^-3 s^-1. Suppose we start with 0.01250 mol of A₂B₅(g) in a volume of 1.5 L. How many moles of A₂B₅ will remain after 3.0 min?

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The first-order rate constant for the decomposition of the hypothetical compound A2B5, 2 A2B5(g) → 4 AB2(g) + B2(g), at 70 °C is 2.34 × 10-3 s-1. Suppose we start with 0.01250 mol of A2B5(g) in a volume of 1.5 L. How many moles of A2B5 will remain after 3.0 min?

The first-order rate constant for the decomposition of the hypothetical compound A₂B₅, 2 A₂B₅(g) → 4 AB₂(g) + B₂(g), at 70 °C is 2.34 × 10^-3 s^-1. Suppose we start with 0.01250 mol of A₂B₅(g) in a volume of 1.5 L. How many moles of A₂B₅ will remain after 3.0 min?