Given the following formation reactions and their enthalpies of formation

(reaction 1) 1/2 H₂ (g) + 1/2 Cl₂ (g) → HCl (g)                      ΔH = –92.3 kJ

(reaction 2) C (s) + 2 Cl₂ (g) → CCl₄ (g)                              ΔH = –95.7 kJ

(reaction 3) C (s) + 1/2 H₂ (g) + 3/2 Cl₂ (g) → CHCl₃ (g)     ΔH = –102.7 kJ

find ΔH for the reaction:

CHCl₃ (g) + Cl₂ (g) → HCl (g) + CCl₄ (g)