calculate-the-ph-and-the-molarities-of-all-species-h3aso4-h2aso3-haso42-aso43-h3

Question

K_a1 = 6.46×10^–3

K_a2 = 1.14×10^–7

K_a3 = 3.16×10^–12

Accepted Answer

[H₃AsO₄] = 0.672 M
[H₂AsO₃^–] = 0.0659 M
[HAsO₄^2–] = 1.14×10^–7 M
[AsO₄^3–] = 5.47×10^–18 M
[H₃O⁺] = 0.0659 M
[OH^–] = 1.52×10^–13 M
pH = 1.181

Answer

[H₃AsO₄] = 0.672 M
[H₂AsO₃^–] = 0.0659 M
[HAsO₄^2–] = 1.14×10^–7 M
[AsO₄^3–] = 5.47×10^–18 M
[H₃O⁺] = 0.0659 M
[OH^–] = 2.52×10^–13 M
pH = 2.181

Answer

[H₃AsO₄] = 0.714 M
[H₂AsO₃^–] = 0.0812 M
[HAsO₄^2–] = 1.14×10^–7 M
[AsO₄^3–] = 5.47×10^–18 M
[H₃O⁺] = 0.0659 M
[OH^–] = 2.52×10^–13 M
pH = 2.181

Answer

[H₃AsO₄] = 0.714 M
[H₂AsO₃^–] = 0.0812 M
[HAsO₄^2–] = 1.14×10^–7 M
[AsO₄^3–] = 6.18×10^–18 M
[H₃O⁺] = 0.0812 M
[OH^–] = 2.52×10^–13 M
pH = 3.181