reaction-a-has-an-activation-energy-of-80-kj-mol-at-500-k-find-the-fraction-of-t

Question

A particular reaction has an activation energy equal to 80 kJ/mol at 500 K. Find the fraction of the molecules in a gas that will collide with an energy equal to or greater than the activation energy at 500 K. If the activation energy at the same temperature is 160 kJ/mol, determine the value of this fraction.

Accepted Answer

For E_a = 80 kJ/mol, fraction = 4.39×10⁻⁹
For E_a = 160 kJ/mol, fraction = 1.92×10⁻¹⁷

Answer

For E_a = 80 kJ/mol, fraction = 3.57×10⁻¹¹
For E_a = 160 kJ/mol, fraction = 1.27×10⁻²¹

Answer

For E_a = 80 kJ/mol, fraction = 1.08×10⁻⁷
For E_a = 160 kJ/mol, fraction = 1.18×10⁻¹⁴

Answer

For E_a = 80 kJ/mol, fraction = 7.59×10⁻⁷
For E_a = 160 kJ/mol, fraction = 1.15×10⁻¹²

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