Skip to main content
10. Periodic Properties of the Elements - Part 3 of 3
10. Periodic Properties of the Elements / Periodic Trend: Successive Ionization Energies / Problem 4

Consider the following successive ionization energies for an element in the third period of the periodic table. Determine the name of the element.

Ea1 = 577.5 kJ/mol
Ea2 = 1,816.7 kJ/mol
Ea3 = 2,744.8 kJ/mol
Ea4 = 11,577 kJ/mol
Ea5 = 14,842 kJ/mol
Ea6 = 18,379 kJ/mol
Ea7 = 23,326 kJ/mol

ANSWERS OPTIONS
Was this helpful?
Learn this concept