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Ch.13 - Properties of Solutions
Chapter 13, Problem 104b

Carbon disulfide (CS2) boils at 46.30 °C and has a density of 1.261 g/mL. (b) When 5.39 g of a nondissociating unknown is dissolved in 50.0 mL of CS2, the solution boils at 47.08 °C. What is the molar mass of the unknown?

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First, identify the boiling point elevation formula: ΔT_b = i * K_b * m, where ΔT_b is the boiling point elevation, i is the van't Hoff factor (which is 1 for a nondissociating solute), K_b is the ebullioscopic constant of the solvent, and m is the molality of the solution.
Calculate the boiling point elevation, ΔT_b, by subtracting the boiling point of pure CS2 from the boiling point of the solution: ΔT_b = 47.08 °C - 46.30 °C.
Determine the molality (m) of the solution using the formula: m = moles of solute / kg of solvent. First, convert the volume of CS2 to mass using its density: mass of CS2 = 50.0 mL * 1.261 g/mL.
Rearrange the boiling point elevation formula to solve for the molality: m = ΔT_b / (i * K_b). You will need the ebullioscopic constant (K_b) for CS2, which can be found in a reference source.
Finally, calculate the molar mass of the unknown solute using the formula: molar mass = mass of solute / moles of solute. Use the molality and the mass of the solvent to find the moles of solute, and then use the given mass of the solute (5.39 g) to find its molar mass.

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