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Ch.8 - Basic Concepts of Chemical Bonding

Chapter 8, Problem 4a

The orbital diagram that follows shows the valence electrons for a 2+ ion of an element. (a) What is the element?

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Hello everyone today. We have the valence electron configuration of an eye on having a positive one charge being shown below. Using the diagram, we are then asked to identify the element. So the diagram shows an empty Pew orbital, Which means that if we were to add back that lost electron, the positive one charge here, we would add one electron to the five p orbital. So from this we can determine that we are in the fifth period on the periodic table, the horizontal rows. We also know that we are in the P block and we also see that in the P block we only have one electron present and so that must correspond with Group three A. Using these identifying clues, we can then infer that the identity of the element is indium N. D. M. Or I. N. As the symbol. I hope this helped and until next time.
Related Practice
Textbook Question

Illustrated are four ions — A, B, X, and Y— showing their relative ionic radii. The ions shown in red carry positive charges: a 2+ charge for A and a 1+ charge for B. Ions shown in blue carry negative charges: a 1- charge for X and a 2- charge for Y. (b) Among the combinations in part (a), which leads to the ionic compound having the largest lattice energy?

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Textbook Question

A portion of a two-dimensional 'slab' of NaCl(s) is shown here (see Figure 8.2) in which the ions are numbered. (a) Which colored balls must represent sodium ions?

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Textbook Question

A portion of a two-dimensional 'slab' of NaCl(s) is shown here (see Figure 8.2) in which the ions are numbered. (d) Consider ion 5. How many repulsive interactions are shown for it?

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Textbook Question

In the Lewis structure shown here, A, D, E, Q, X, and Z represent elements in the first two rows of the periodic table. Identify all six elements so that the formal charges of all atoms are zero.

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Textbook Question

The partial Lewis structure that follows is for a hydrocarbon molecule. In the full Lewis structure, each carbon atom satisfies the octet rule, and there are no unshared electron pairs in the molecule. The carbon—carbon bonds are labeled 1, 2, and 3. (a) How many hydrogen atoms are in the molecule?

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Textbook Question

The partial Lewis structure that follows is for a hydrocarbon molecule. In the full Lewis structure, each carbon atom satisfies the octet rule, and there are no unshared electron pairs in the molecule. The carbon—carbon bonds are labeled 1, 2, and 3. (c) Which carbon—carbon bond is the strongest one?

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