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Ch.10 - Gases
Chapter 10, Problem 92

Based on their respective van der Waals constants ( Table 10.3), is Ar or CO2 expected to behave more nearly like an ideal gas at high pressures?

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insert step 1> Identify the van der Waals equation, which is an adjustment of the ideal gas law to account for the volume occupied by gas molecules and the intermolecular forces between them. The equation is: \( \left( P + \frac{an^2}{V^2} \right)(V - nb) = nRT \), where \( a \) and \( b \) are the van der Waals constants.
insert step 2> Understand that the constant \( a \) accounts for the attractive forces between molecules. A smaller \( a \) value indicates weaker intermolecular forces, making the gas behave more ideally.
insert step 3> Recognize that the constant \( b \) accounts for the volume occupied by the gas molecules themselves. A smaller \( b \) value suggests that the gas molecules occupy less volume, making the gas behave more ideally.
insert step 4> Compare the van der Waals constants \( a \) and \( b \) for Ar and CO2 from Table 10.3. Determine which gas has smaller values for both constants, as this gas will behave more like an ideal gas at high pressures.
insert step 5> Conclude which gas, Ar or CO2, is expected to behave more nearly like an ideal gas at high pressures based on the comparison of their van der Waals constants.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Ideal Gas Law

The Ideal Gas Law describes the behavior of ideal gases through the equation PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature. Ideal gases are assumed to have no intermolecular forces and occupy no volume, making them behave predictably under various conditions. Understanding this law is crucial for comparing real gases to ideal behavior, especially at high pressures.
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Van der Waals Equation

The Van der Waals equation modifies the Ideal Gas Law to account for the volume occupied by gas molecules and the attractive forces between them. It introduces two constants, a and b, which are specific to each gas and reflect the strength of intermolecular forces and the size of the molecules, respectively. This equation helps predict how real gases deviate from ideal behavior, particularly under high pressure and low temperature.
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Intermolecular Forces

Intermolecular forces are the attractive or repulsive forces between molecules that influence their physical properties and behavior. In the context of gases, stronger intermolecular forces can lead to greater deviations from ideal gas behavior, especially at high pressures where molecules are closer together. Understanding these forces is essential for predicting whether a gas like Ar or CO2 will behave more ideally under specific conditions.
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Related Practice
Textbook Question

(b) List two reasons why the gases deviate from ideal behavior.

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Textbook Question

The planet Jupiter has a surface temperature of 140 K and a mass 318 times that of Earth. Mercury (the planet) has a surface temperature between 600 K and 700 K and a mass 0.05 times that of Earth. On which planet is the atmosphere more likely to obey the ideal-gas law? Explain.

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Textbook Question

Which statement concerning the van der Waals constants a and b is true? (a) The magnitude of a relates to molecular volume, whereas b relates to attractions between molecules. (b) The magnitude of a relates to attractions between molecules, whereas b relates to molecular volume. (c) The magnitudes of a and b depend on pressure. (d) The magnitudes of a and b depend on temperature.

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Open Question
In Sample Exercise 10.16, we found that one mole of Cl2 confined to 22.41 L at 0 °C deviated slightly from ideal behavior. Calculate the pressure exerted by 1.00 mol Cl2 confined to a smaller volume, 5.00 L, at 25 °C. (a) Use the ideal gas law for the calculation. (b) Then use the van der Waals equation for your calculation. (Values for the van der Waals constants are given in Table 10.3.) (c) Why is the difference between the result for an ideal gas and that calculated using the van der Waals equation greater when the gas is confined to 5.00 L compared to 22.41 L?
Textbook Question

Calculate the pressure that CCl4 will exert at 80 °C if 1.00 mol occupies 33.3 L, assuming that (a) CCl4 obeys the ideal-gas equation (b) CCl4 obeys the van der Waals equation. (Values for the van der Waals constants are given in Table 10.3.)

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Textbook Question

Table 10.3 shows that the van der Waals b parameter has units of L/mol. This means that we can calculate the sizes of atoms or molecules from the b parameter. Refer back to the discussion in Section 7.3. Is the van der Waals radius we calculate from the b parameter of Table 10.3 more closely associated with the bonding or nonbonding atomic radius discussed there? Explain.

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