How much heat (in kJ) is required to warm 10.0 g of ice, initially at -10.0 °C, to steam at 110.0 °C? The heat capacity of ice is 2.09 J/g°C, and that of steam is 2.01 J/g°C.

Verified step by step guidance

1. Calculate the heat required to warm the ice from -10.0 °C to 0 °C using q = m * c * ΔT, where m is the mass, c is the specific heat capacity of ice, and ΔT is the temperature change.
2. Calculate the heat required to melt the ice at 0 °C to water using q = m * ΔH_fus, where ΔH_fus is the heat of fusion for water.
3. Calculate the heat required to warm the water from 0 °C to 100 °C using q = m * c * ΔT, where c is the specific heat capacity of water.
4. Calculate the heat required to vaporize the water at 100 °C to steam using q = m * ΔH_vap, where ΔH_vap is the heat of vaporization for water.
5. Calculate the heat required to warm the steam from 100 °C to 110 °C using q = m * c * ΔT, where c is the specific heat capacity of steam.