Ch.12 - Solids and Modern Material
Chapter 12, Problem 84
When spheres of radius r are packed in a body-centered cubic arrangement, they occupy 68.0% of the available volume. Use the fraction of occupied volume to calculate the value of a, the length of the edge of the cube, in terms of r.
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Understand that in a body-centered cubic (BCC) arrangement, there is one atom at each corner of the cube and one atom in the center.
Recognize that the volume occupied by the spheres is 68.0% of the total volume of the cube.
The volume of a single sphere is given by \( \frac{4}{3} \pi r^3 \). In a BCC unit cell, there are effectively 2 spheres (1/8 of a sphere at each of the 8 corners and 1 whole sphere in the center).
The total volume of the cube is \( a^3 \), where \( a \) is the edge length of the cube.
Set up the equation for the fraction of occupied volume: \( \frac{2 \times \frac{4}{3} \pi r^3}{a^3} = 0.68 \) and solve for \( a \) in terms of \( r \).
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