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Ch.14 - Chemical Kinetics
Chapter 14, Problem 85

Consider the reaction: A + B + C → D. The rate law for this reaction is: Rate = k [A][C]^2 [B]^1/2. Suppose the rate of the reaction at certain initial concentrations of A, B, and C is 0.0115 M/s. What is the rate of the reaction if the concentrations of A and C are doubled and the concentration of B is tripled?

Verified step by step guidance
1
Identify the given rate law: Rate = k [A][C]^2 [B]^{1/2}.
Note the initial rate of the reaction: 0.0115 M/s.
Determine the effect of doubling the concentration of A: The rate will be multiplied by 2, since the reaction is first order with respect to A.
Determine the effect of doubling the concentration of C: The rate will be multiplied by 2^2 = 4, since the reaction is second order with respect to C.
Determine the effect of tripling the concentration of B: The rate will be multiplied by (3)^{1/2}, since the reaction is half order with respect to B.

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Rate Law

The rate law of a chemical reaction expresses the relationship between the reaction rate and the concentrations of the reactants. It is typically formulated as Rate = k [A]^m [B]^n [C]^p, where k is the rate constant, and m, n, and p are the reaction orders with respect to each reactant. Understanding the rate law is essential for predicting how changes in concentration affect the reaction rate.
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Reaction Order

Reaction order refers to the exponent of a reactant's concentration in the rate law, indicating how the rate of reaction is affected by that reactant. For example, in the rate law Rate = k [A][C]^2 [B]^1/2, the reaction is first order with respect to A, second order with respect to C, and half order with respect to B. This concept is crucial for calculating the new rate when concentrations change.
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Concentration Changes

Changes in the concentrations of reactants directly influence the rate of a reaction according to the rate law. In this scenario, if the concentrations of A and C are doubled and B is tripled, the new rate can be calculated by substituting these new concentrations into the rate law. Understanding how to manipulate these concentrations is key to determining the new reaction rate.
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Related Practice
Open Question
What is the half-life for this reaction at the initial concentration?
Textbook Question

The tabulated data were collected for this reaction at a certain temperature: X2Y → 2 X + Y a. Determine the order of the reaction and the value of the rate constant at this temperature.

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Textbook Question

The tabulated data were collected for this reaction at a certain temperature: X2Y → 2 X + Y c. What is the concentration of X after 10.0 hours?

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Textbook Question

Consider the reaction: 2 O3(g) → 3 O2( g) The rate law for this reaction is: Rate = k [O3]2 [O2] Suppose that a 1.0-L reaction vessel initially contains 1.0 mol of O3 and 1.0 mol of O2. What fraction of the O3 will have reacted when the rate falls to one-half of its initial value?

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Open Question
At 700 K, acetaldehyde decomposes in the gas phase to methane and carbon monoxide. The reaction is: CH3CHO(g) → CH4(g) + CO(g). A sample of CH3CHO is heated to 700 K and the pressure is measured as 0.22 atm before any reaction takes place. The kinetics of the reaction are followed by measurements of total pressure and these data are obtained: t (s) 0 1000 3000 7000; PTotal (atm) 0.22 0.24 0.27 0.31. Find the rate law, the rate constant, and the total pressure after 2.00 × 10^4 s.
Open Question
At 400 K, oxalic acid decomposes according to the reaction: H2C2O4(g) → CO2(g) + HCOOH(g). In three separate experiments, the initial pressure of oxalic acid and the final total pressure after 20,000 seconds are measured. Experiment: 1) PH2C2O4 at t = 0: 65.8, PTotal at t = 20,000 s: 94.6; 2) PH2C2O4 at t = 0: 92.1, PTotal at t = 20,000 s: 132; 3) PH2C2O4 at t = 0: 111, PTotal at t = 20,000 s: 160. Find the rate law of the reaction and its rate constant.