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Ch.11 - Liquids & Phase Changes

Chapter 11, Problem 35

The dipole moment of methanol is m = 1.70 D. Use arrows to indicate the direction in which electrons are displaced.

3D model of methanol showing molecular structure and dipole moment direction.

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Video transcript

Hello everyone today. We have the following problem. Acetone has a dipole moment of 1. W units show the direction of the net electron displacement using arrows. So the first thing we wanna do is we want to construct the skeletal structure of acetone. In other words, we wanted to see how this looks when we draw out in louis dot structure format. So we're going to have a method Which is a carbon bonded to three hydrogen. We're going to have a metal bonded to a central carbon and that central carbon is going to be bonded to or double bonded to an oxygen as well as another method to determine the net electron displacement, we have to look at electro negativity, electro negativity trends. So according to the periodic table, electro negativity increases from down upwards of a group and electro negativity increases from left to write. And according to the positions of these atoms here, we can determine that oxygen is more electro negative than carbon. So we can say that oxygen is more electro negative than carbon and this means that it will attract electrons towards it. And so to denote that we're gonna draw an arrow from the carbon to the oxygen. And then we're going to draw a line at the base of that arrow. And so with that we have constructed our diagram and shown the net electron displacement overall, I hope that this helped. And until next time
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Textbook Question
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