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Ch.19 - Electrochemistry

Chapter 19, Problem 97

Make a sketch of an electrolysis cell that electroplates copper onto other metal surfaces. Label the anode and the cathode and indicate the reactions that occur at each.

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Hi everyone for this problem it reads which cell represents an electrolysis cell that electro plates, zinc. Okay, so here we are dealing with an electrolysis cell. So let's just define what that is. That is when a cell converts electrical energy into chemical energy. And this word here, electro plates basically means it's a process of plating a metal onto the other by hydraulic sis. Okay, so we need to identify which one represents that. So we'll go ahead and get started. So here we're going to be dealing with an an Oid and a cath Oid and are an Oid equals our positive side and our cath Oid equals are negative side. Okay, so for Electoral ISIS this is a redox reaction that's not spontaneous. And so electrical energy has to be supplied to initiate the reaction. So taking a look a look at our answer choices for Electoral ISIS. We're going to want to choose the one with a voltage source. So here we see that we have some with a voltage source and some with a volt meter. So having a volt meter means that it's measuring the voltage generated by the cell, which is not electrolysis. So we can go ahead and automatically get rid of our answer choices that contain a volt meter because those do not represent electrolytic cells. The next thing that happens with the Electoral license is there is going to be half reactions. Okay, so are we can start off with our an Oid are an Oid is going to B oxidation. Okay, so this one is going to be undergo oxidation and this one is the catholic is going to undergo reduction. Okay. And so we can start off with our half reaction for oxidation. So for this one we have our zinc and remember our acronym oil rig oxidation is loss reduction is gained and we're dealing with electrons here. So because our an Oid is undergoing oxidation, it is going to lose two electrons because oxidation is lost. So this one becomes zinc, two plus Plus two electrons. And on the other hand are Catholic, this that's where our reduction takes place. And remember reduction is gain. So we're going to gain two electrons. Okay, so we'll start off with our zinc two plus ion. We're going to gain two electrons and this is going to become solid zinc. So we need to make sure our two half reactions match the images shown. Okay, so we already eliminated A and D. So let's take a look at what we have left. So for B we see it says are an oid, is that which is not correct? And our catholic oid so it's reversed. Okay, so B is not going to be correct because it does not reflect the correct half reactions. So that leaves us with answer choice C. So let's take a look. Okay, so we have a voltage source and we have the correct half reactions. Okay, so that's going to make answer choice C. Are correct option. That is it for this problem. I hope this was helpful