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Ch.13 - Solutions
Chapter 13, Problem 88

Is the question formulated correctly for calculating the freezing point and boiling point of each solution, assuming complete dissociation of the solute? For the following: a. 10.5 g FeCl3 in 1.50 * 10^2 g water b. 3.5% KCl by mass (in water) c. 0.150 m MgF2.

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<insert step 1> Determine the molality (m) of each solution. For FeCl3, calculate the number of moles of FeCl3 using its molar mass, then divide by the mass of water in kilograms. For KCl, use the given mass percentage to find the mass of KCl in 100 g of solution, then calculate molality. For MgF2, the molality is already given as 0.150 m.>
<insert step 2> Calculate the van't Hoff factor (i) for each solute, which represents the number of particles the solute dissociates into. For FeCl3, i = 4 (Fe^3+ and 3 Cl^-). For KCl, i = 2 (K^+ and Cl^-). For MgF2, i = 3 (Mg^2+ and 2 F^-).>
<insert step 3> Use the freezing point depression formula: \( \Delta T_f = i \cdot K_f \cdot m \), where \( K_f \) is the cryoscopic constant for water. Calculate \( \Delta T_f \) for each solution.>
<insert step 4> Use the boiling point elevation formula: \( \Delta T_b = i \cdot K_b \cdot m \), where \( K_b \) is the ebullioscopic constant for water. Calculate \( \Delta T_b \) for each solution.>
<insert step 5> Determine the new freezing and boiling points by subtracting \( \Delta T_f \) from the normal freezing point of water (0°C) and adding \( \Delta T_b \) to the normal boiling point of water (100°C).>