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Learn the toughest concepts covered in Chemistry with step-by-step video tutorials and practice problems by world-class tutors

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Ch.1 - Chemical Tools: Experimentation & Measurement

Ch.2 - Atoms, Molecules & Ions

Ch.3 - Mass Relationships in Chemical Reactions

BONUS: Lab Techniques and Procedures

BONUS: Mathematical Operations and Functions

Ch.4 - Reactions in Aqueous Solution

Ch.5 - Periodicity & Electronic Structure of Atoms

Ch.6 - Ionic Compounds: Periodic Trends and Bonding Theory

Ch.7 - Covalent Bonding and Electron-Dot Structures

Ch.8 - Covalent Compounds: Bonding Theories and Molecular Structure

Ch.9 - Thermochemistry: Chemical Energy

Ch.10 - Gases: Their Properties & Behavior

Ch.11 - Liquids & Phase Changes

Ch.12 - Solids and Solid-State Materials

Ch.13 - Solutions & Their Properties

Ch.14 - Chemical Kinetics

Ch.15 - Chemical Equilibrium

Ch.16 - Aqueous Equilibria: Acids & Bases

Ch.17 - Applications of Aqueous Equilibria

Ch.18 - Thermodynamics: Entropy, Free Energy & Equilibrium

Ch.19 - Electrochemistry

Ch.20 - Nuclear Chemistry

Ch.21 - Transition Elements and Coordination Chemistry

Ch.22 - The Main Group Elements

Ch.23 - Organic and Biological Chemistry

Titrations: Diprotic & Polyprotic Buffers

Titrations of Diprotic and Polyprotic Acids

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Chapter 17, Problem 11

The pH titration curve applies to the titration of 40.0 mL of a 0.100 M solution of an acid with 0.100 M NaOH. What are the approximate pKa values for this acid?
(a) pKa1 = 5, pKa2 = 10 (b) pKa1 = 7, pKa2 = 11 (c) pKa1 = 5, pKa2 = 10, pKa3 = 13 (d) pKa1 = 5, pKa2 = 7, pKa3 = 10

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Chapter 17, Problem 11

The pH titration curve applies to the titration of 40.0 mL of a 0.100 M solution of an acid with 0.100 M NaOH. What are the approximate pKa values for this acid? (a) pKa1 = 5, pKa2 = 10 (b) pKa1 = 7, pKa2 = 11 (c) pKa1 = 5, pKa2 = 10, pKa3 = 13 (d) pKa1 = 5, pKa2 = 7, pKa3 = 10

The pH titration curve applies to the titration of 40.0 mL of a 0.100 M solution of an acid with 0.100 M NaOH. What are the approximate pKa values for this acid?
(a) pKa1 = 5, pKa2 = 10 (b) pKa1 = 7, pKa2 = 11 (c) pKa1 = 5, pKa2 = 10, pKa3 = 13 (d) pKa1 = 5, pKa2 = 7, pKa3 = 10