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Ch.13 - Solutions & Their Properties
Chapter 13, Problem 149c

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (c) What is the molality of particles (ions) in the solution of MClx?

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Identify the freezing point depression formula: \( \Delta T_f = i \cdot K_f \cdot m \), where \( \Delta T_f \) is the change in freezing point, \( i \) is the van't Hoff factor, \( K_f \) is the cryoscopic constant of water (1.86 °C kg/mol), and \( m \) is the molality.
Calculate the change in freezing point: \( \Delta T_f = 0.0 \text{ °C} - (-3.53 \text{ °C}) = 3.53 \text{ °C} \).
Rearrange the freezing point depression formula to solve for molality: \( m = \frac{\Delta T_f}{i \cdot K_f} \).
Assume the van't Hoff factor \( i \) for \( \text{MCl}_x \) is known or can be determined based on the dissociation of the compound in water.
Substitute the known values into the rearranged formula to calculate the molality: \( m = \frac{3.53}{i \cdot 1.86} \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Gas Laws

Gas laws describe the behavior of gases in relation to pressure, volume, and temperature. The ideal gas law (PV=nRT) is particularly relevant here, as it allows us to calculate the number of moles of gas produced during the reaction. Understanding how to manipulate these variables is essential for determining the amount of gas evolved and its implications for the stoichiometry of the reaction.
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Combined Gas Law

Molality

Molality is a measure of the concentration of solute in a solution, defined as the number of moles of solute per kilogram of solvent. It is crucial for understanding colligative properties, such as freezing point depression, which is indicated by the melting point of the solution in this question. Calculating molality requires knowledge of both the mass of the solute and the mass of the solvent.
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Dissociation of Ionic Compounds

When ionic compounds like MClx dissolve in water, they dissociate into their constituent ions. This dissociation affects the total number of particles in solution, which is important for calculating colligative properties. Understanding how many ions are produced from the dissolution of MClx is necessary to determine the molality of particles in the solution.
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Related Practice
Open Question
The steroid hormone estradiol contains only C, H, and O; combustion analysis of a 3.47 mg sample yields 10.10 mg CO2 and 2.76 mg H2O. When dissolving 7.55 mg of estradiol in 0.500 g of camphor, the melting point of camphor is depressed by 2.10 °C. What is the molecular weight of estradiol, and what is a probable formula? [For camphor, Kf = 37.7 °C kg/mol.]
Textbook Question
Addition of 50.00 mL of 2.238 m H2SO4 1solution density = 1.1243 g>mL2 to 50.00 mL of 2.238 M BaCl2 gives a white precipitate. (b) If you filter the mixture and add more H2SO4 solution to the filtrate, would you obtain more precipitate? Explain.
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Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dissolving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (b) What mass of MClx is formed? (a) How many moles of H2 gas are evolved?

Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (e) What are the formula and molecular weight of MClx?

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Textbook Question

Treatment of 1.385 g of an unknown metal M with an excess of aqueous HCl evolved a gas that was found to have a volume of 382.6 mL at 20.0 °C and 755 mm Hg pressure. Heating the reaction mixture to evaporate the water and remaining HCl then gave a white crystalline compound, MClx. After dis- solving the compound in 25.0 g of water, the melting point of the resulting solution was - 3.53 °C. (f) What is the identity of the metal M?

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Textbook Question

A compound that contains only C and H was burned in excess O2 to give CO2 and H2O. When 0.270 g of the com- pound was burned, the amount of CO2 formed reacted completely with 20.0 mL of 2.00 M NaOH solution according to the equation 2 OH-1aq2 + CO21g2 S CO 2- 1aq2 + H2O1l2 When 0.270 g of the compound was dissolved in 50.0 g of camphor, the resulting solution had a freezing point of 177.9 °C. [#Pure camphor freezes at 179.8 °C and has Kf = 37.7 1°C kg2>mol.] (a) What is the empirical formula of the compound?

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