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Ch.3 - Molecules, Compounds & Chemical Equations
Chapter 3, Problem 93

What is the empirical formula of nitrogen chloride given that a 0.77 mg sample of nitrogen reacts with chlorine to form 6.61 mg of the chloride?

Verified step by step guidance
1
Determine the mass of chlorine in the compound by subtracting the mass of nitrogen from the total mass of the nitrogen chloride: \(6.61 \text{ mg} - 0.77 \text{ mg}\).
Convert the mass of nitrogen (0.77 mg) to moles using the molar mass of nitrogen (14.01 g/mol).
Convert the mass of chlorine (calculated in step 1) to moles using the molar mass of chlorine (35.45 g/mol).
Calculate the mole ratio of nitrogen to chlorine by dividing the moles of each element by the smallest number of moles calculated in steps 2 and 3.
Use the mole ratio to determine the empirical formula by expressing the ratio as the smallest whole numbers.